Python 2.7报错：'list'对象无'get'方法，CSV写入卡壳求助

It sounds like the root of your CSV writing problem is that you're trying to use the get() method on something that isn't a dictionary—most likely a tuple from iteritems() (or items() in Python 3). Let's break this down and fix it step by step.

Common Mistake: Treating Tuple Pairs as Dictionaries #

When you loop through some_dict.iteritems() (Python 2) or some_dict.items() (Python 3), you get an iterator of (key, value) tuples. These tuples don't have a get() method—only dictionaries do. So if you're trying to do something like item.get('address') where item is one of these tuples, you'll get an error.

Example of the Wrong Approach #

Suppose your scraped data looks like this (a dictionary of courts, where keys are names and values are address details):

courts = {
    "Manchester Crown Court": {"address": "Spinningfields, Manchester M3 3HH"},
    "Birmingham Magistrates' Court": {"address": "Victoria Law Courts, Birmingham B1 3JR"}
}

If you try writing to CSV like this, it will fail:

import csv

with open("courts.csv", "w") as f:
    writer = csv.DictWriter(f, fieldnames=["court_name", "address"])
    writer.writeheader()
    for item in courts.iteritems():  # This gives tuples like ("Manchester Crown Court", {...})
        # Trying to call get() on the tuple will throw an error!
        writer.writerow({"court_name": item.get("name"), "address": item.get("address")})

Corrected Approach #

Instead, unpack the tuple into separate variables for the key and value, then use the value (which is a dictionary) to access the address:

import csv

courts = {
    "Manchester Crown Court": {"address": "Spinningfields, Manchester M3 3HH"},
    "Birmingham Magistrates' Court": {"address": "Victoria Law Courts, Birmingham B1 3JR"}
}

with open("courts.csv", "w", newline="") as f:
    writer = csv.DictWriter(f, fieldnames=["court_name", "address"])
    writer.writeheader()
    # Unpack each (name, details) tuple from the dictionary
    for court_name, details in courts.items():  # Use items() for Python 3, iteritems() for Python 2
        # Access the address using details.get() (since details is a dict)
        row = {
            "court_name": court_name,
            "address": details.get("address", "")  # Use get() to handle missing addresses gracefully
        }
        writer.writerow(row)

If You're Using a List of Dictionaries #

If your scraped data is a list of dictionaries (each representing one court), you can loop through the list directly—no need for iteritems() at all:

import csv

courts = [
    {"court_name": "Manchester Crown Court", "address": "Spinningfields, Manchester M3 3HH"},
    {"court_name": "Birmingham Magistrates' Court", "address": "Victoria Law Courts, Birmingham B1 3JR"}
]

with open("courts.csv", "w", newline="") as f:
    writer = csv.DictWriter(f, fieldnames=["court_name", "address"])
    writer.writeheader()
    for court in courts:
        # court is a dictionary, so get() works here
        writer.writerow({
            "court_name": court.get("court_name", ""),
            "address": court.get("address", "")
        })
        # Or just pass the court dict directly if it has exactly the fieldnames:
        # writer.writerow(court)

Key Takeaways #

1. Stop using iteritems() on the wrong object: If you're working with a list of courts, loop through the list elements (each should be a dict). If you're working with a dict of courts, unpack the (key, value) tuples first.
2. Only call get() on dictionaries: Make sure the variable you're using get() on is actually a dictionary (like the details variable in the first corrected example).
3. Use items() for Python 3: iteritems() was removed in Python 3—replace it with items().

This should resolve the missing get() method error and let you write your court data to CSV successfully.

内容的提问来源于stack exchange，提问作者ron_g