请求协助编写SQL语句：筛选VALUE为1的全部行及VALUE为0的首行

Got it, here's how you can achieve exactly what you need. The approach combines two sets of data: all rows where VALUE equals 1, plus the first row where VALUE equals 0 (using ID to define "first" as shown in your expected result).

-- Fetch all rows with VALUE = 1
SELECT ID, NAME, VALUE, DATE
FROM your_table_name
WHERE VALUE = 1

UNION ALL

-- Fetch the first row with VALUE = 0 (ordered by ID to match your example)
SELECT ID, NAME, VALUE, DATE
FROM your_table_name
WHERE VALUE = 0
ORDER BY ID ASC
LIMIT 1;

Quick Notes: #

• Replace your_table_name with the actual name of your table.
• If "first row" should be determined by a different column (like DATE instead of ID), just adjust the ORDER BY clause in the second query to use that column.
• Using UNION ALL instead of UNION is more efficient here since the two result sets are mutually exclusive (no overlap between VALUE=1 and VALUE=0 rows), so we don’t need to waste resources removing duplicates.

内容的提问来源于stack exchange，提问作者MacRtor