求助：基于Eclipse的十进制转二进制转换器类实现问题

Hey there! Let's get your decimal-to-binary converter assignment sorted out. Based on the algorithm you provided, here's a complete, working implementation of the DecToBinConverter class in Java (perfect for your Eclipse project):

First, let's restate the requirements clearly to make sure we cover everything:

• Create a class named DecToBinConverter
• Include a public static void method printInBinary(int n)
• Implement this algorithm:
  1. Initialize an empty Integer stack S
  2. If n is 0, output 0
  3. While n > 0:
     a. Calculate rem = n % 2
     b. Push rem to stack S
     c. Update n = n / 2
  4. While stack S is not empty:
     a. Pop a digit from S
     b. Print the digit

import java.util.Stack;

public class DecToBinConverter {
    public static void printInBinary(int n) {
        // Step 1: Initialize empty Integer stack
        Stack<Integer> binaryStack = new Stack<>();
        
        // Step 2: Handle the special case where n is 0
        if (n == 0) {
            System.out.println(0);
            return;
        }
        
        // Step 3: Push remainders to the stack as we divide by 2
        while (n > 0) {
            int remainder = n % 2;
            binaryStack.push(remainder);
            n = n / 2; // Integer division automatically truncates the decimal
        }
        
        // Step 4: Pop digits from the stack to print the binary number in correct order
        while (!binaryStack.isEmpty()) {
            int digit = binaryStack.pop();
            System.out.print(digit);
        }
        // Add a newline after the binary output for readability
        System.out.println();
    }
    
    // Optional test method to verify functionality
    public static void main(String[] args) {
        // Test some common values
        printInBinary(0);    // Output: 0
        printInBinary(7);    // Output: 111
        printInBinary(16);   // Output: 10000
        printInBinary(42);   // Output: 101010
    }
}

• Why the stack? When we divide by 2, we get the least significant bit first. The stack's LIFO (last-in, first-out) property lets us reverse this order to print the binary number from most to least significant bit.
• Special case for 0: If we didn't handle n=0 separately, the stack would stay empty and nothing would print—this fixes that.
• Integer division: Using n = n / 2 works because integer division in Java automatically drops the fractional part, which is exactly what we need when converting decimal to binary.

Just drop this class into your Eclipse project, and it should meet all your assignment requirements. You can run the main method to test it with different values too!

内容的提问来源于stack exchange，提问作者TWangmo