如何在Notepad++中查找文件内包含下划线的重复单词

Got it, let's figure out how to find those duplicate underscore-containing words across your entire file. From your example with #define directives, it sounds like you're targeting identifiers like FF_EIS_DMC_1_TERRAIN_AHEAD_TIME that show up more than once. Here are a few practical, tested methods to solve this:

1. Command Line: Grep + Sort + Uniq (Classic Approach) #

This is a go-to for text processing tasks, especially if you're working in a terminal. It breaks down the problem into extracting, sorting, and filtering duplicates:

For your #define-specific scenario: #

If your lines follow the exact format #define [number] [identifier] [comment], use this command to target only those underscore-containing identifiers:

grep -E '#define [0-9]+ ([A-Z_0-9]+)' your_file.h | awk '{print $3}' | sort | uniq -d

Let's break this down:

• grep -E uses extended regex to match valid #define lines
• awk '{print $3}' pulls out the third field (your target identifier with underscores)
• sort groups duplicate identifiers together
• uniq -d only outputs lines that appear more than once

For a general case (any underscore-containing word in the file): #

If you need to scan the entire file for any word with underscores that repeats, use:

grep -oE '[A-Za-z0-9_]+' your_file | grep '_' | sort | uniq -d

• grep -oE extracts individual words made of letters, numbers, and underscores
• The second grep '_' filters to only keep words with underscores
• sort + uniq -d handles finding duplicates as before

2. Command Line: Awk (Single-Tool Efficiency) #

Awk can handle the entire workflow in one command, which is faster for large files. It counts occurrences on the fly and outputs duplicates directly:

#define-specific version: #

awk '/^#define/ {if ($3 ~ /_/) count[$3]++} END {for (word in count) if (count[word] > 1) print word}' your_file.h

• We check for lines starting with #define, then verify the third field has an underscore
• We increment a counter for each identifier
• At the end, we print any identifier that was counted more than once

General version: #

awk '/_/ {count[$0]++} END {for (word in count) if (count[word] > 1) print word}' your_file

This scans every line, counts occurrences of any line containing an underscore, and outputs duplicates. Adjust the regex /[_]/ if you need to target full words instead of lines.

3. GUI Editor: VS Code (Visual Approach) #

If you prefer a graphical tool, VS Code's regex-powered search can find duplicates across the entire file:

• Open your file and press Ctrl+F (or Cmd+F on Mac)
• Click the .* button to enable regex mode
• Paste this regex into the search bar: \b([A-Za-z0-9_]+)\b(?=.*\b\1\b)
• (Optional) Check "Match Case" if your identifiers are all uppercase, like in your example
• VS Code will highlight every instance of a duplicate underscore-containing word

This regex works by matching a word, then checking if that same word appears later in the file (using a positive lookahead and backreference \1).

内容的提问来源于stack exchange，提问作者Maverick283