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思科C语言课程疑问:mystrcat函数中--destination的用法及逻辑解析

解析自定义mystrcat函数的逻辑,尤其是--destination的用法

Let's walk through this handwritten mystrcat function step by step—this is a replica of the standard library's strcat function, which appends the source string to the end of the destination string and returns the starting address of the modified destination.

第一步:保存起始地址,找到destination的末尾

First, let's break down the first loop:

for(res = destination; *destination++; ) ;
  • res = destination: We store the original starting address of destination in res right away. This is crucial because we're going to move the destination pointer around later, and we need to return the original start of the string when we're done.
  • The loop condition *destination++ works like this: we first read the character that destination is pointing to, then increment the destination pointer by one. The loop keeps running as long as the character we read is not the null terminator \0 (since \0 evaluates to false in C).
  • Key detail: When this loop finishes, destination is pointing to the position after the \0 of the original destination string—not the \0 itself. That's exactly why we need the --destination line next.

第二步:修正指针位置,完成字符串拼接

Now the second loop, where the --destination you're curious about comes into play:

for(--destination; (*destination++ = *source++); ) ;
  • --destination: This moves the destination pointer back one position, so it's now pointing directly at the original \0 of the destination string. This lets us overwrite that \0 with the first character of source, which is how we start appending the new string.
  • The loop condition (*destination++ = *source++) is a clever assignment trick:
    1. We take the character that source is pointing to
    2. Assign it to the position destination is pointing to
    3. Increment both destination and source pointers by one
    4. The value of this entire expression is the character we just assigned. As long as that character isn't \0, the loop continues. When we hit the \0 at the end of source, the expression evaluates to false, and the loop stops—this conveniently copies the \0 to the end of the new combined string, which is exactly what we need for a valid C string.

最后:返回原始起始地址

return res; Since we saved the original start of destination in res at the beginning, returning it gives the caller the starting address of the fully concatenated string—just like the standard strcat does.

A quick example to make it concrete

Let's say destination points to "Hello" (memory layout: H e l l o \0) and source points to "World" (W o r l d \0):

  1. After the first loop, destination is pointing to the spot right after the \0 of "Hello".
  2. --destination moves it back to the \0 position.
  3. The second loop copies W, o, r, l, d, and finally \0 into destination's memory, one by one.
  4. We return res, which points to the start of the new string "HelloWorld".

内容的提问来源于stack exchange,提问作者Hiren Chafekar

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最近更新时间:2026.05.21 07:01:33