如何基于现有LINQ查询实现分组拼接(Group Concatenation)
Great question! Let's break down how to add group concatenation to your existing LINQ query, with examples tailored to both in-memory (LINQ to Objects) and Entity Framework scenarios.
First, Recap Your Base Query
Your existing query filters ReferralDetails by status, joins with ReferralRepository, and orders results. We'll build on this to add grouping and concatenation.
Scenario 1: LINQ to Objects (In-Memory Data)
If your data is already loaded into memory (or you don't mind fetching it first), string.Join is the simplest way to concatenate values per group. Here's how to modify your query:
// Build your base joined query and project needed fields var baseQuery = from t1 in _unitOfWork.ReferralDetailsRepository.Get() .Where(m => (m.ChartStatusID == (int)Utility.ReferralChartStatus.NotStaffed || m.ChartStatusID == (int)Utility.ReferralChartStatus.Partially_Staffed || m.ChartStatusID == (int)Utility.ReferralChartStatus.Restaff) && !m.IsDeleted) .OrderByDescending(x => x.ReferralDetailsId) join t2 in _unitOfWork.ReferralRepository.Get() on t1.ReferralId equals t2.ReferralId // Add any additional joins here (e.g., t3) join t3 in _unitOfWork.SomeOtherRepo.Get() on t1.SomeId equals t3.SomeId // Project only the fields you need for grouping and concatenation select new { ReferralId = t2.ReferralId, ReferralNumber = t2.ReferralNumber, // Replace with the field you want to concatenate (e.g., staff names, notes) FieldToConcatenate = t1.AssignedStaffName }; // Group by your target key (e.g., ReferralId) and concatenate values var lstAssignmentDetails = baseQuery .GroupBy(item => item.ReferralId) .Select(group => new { ReferralId = group.Key, ReferralNumber = group.First().ReferralNumber, // Assumes this value is consistent per group // Join all values in the group with a separator (e.g., ", ") ConcatenatedValues = string.Join(", ", group.Select(g => g.FieldToConcatenate)) }) .ToList();
Scenario 2: Entity Framework (LINQ to Entities)
If you're using EF Core 3.0+, string.Join is directly supported and will translate to SQL's STRING_AGG function (for SQL Server 2017+). For older EF versions, you'll need to either load data to memory first or use Aggregate.
EF Core 3.0+ (Direct SQL Translation)
var lstAssignmentDetails = (from t1 in _unitOfWork.ReferralDetailsRepository.Get() .Where(m => (m.ChartStatusID == (int)Utility.ReferralChartStatus.NotStaffed || m.ChartStatusID == (int)Utility.ReferralChartStatus.Partially_Staffed || m.ChartStatusID == (int)Utility.ReferralChartStatus.Restaff) && !m.IsDeleted) join t2 in _unitOfWork.ReferralRepository.Get() on t1.ReferralId equals t2.ReferralId // Add other joins as needed group t1 by t2.ReferralId into referralGroup select new { ReferralId = referralGroup.Key, // Get other group-level fields (use First() if consistent per group) ReferralNumber = referralGroup.First().Referral.ReferralNumber, // Translates to SQL STRING_AGG ConcatenatedStaffNames = string.Join(", ", referralGroup.Select(t => t.AssignedStaffName)) }) .ToList();
Older EF Versions (Load to Memory First)
If string.Join isn't supported, fetch the base data to memory first with AsEnumerable(), then apply grouping:
var lstAssignmentDetails = _unitOfWork.ReferralDetailsRepository.Get() .Where(m => (m.ChartStatusID == (int)Utility.ReferralChartStatus.NotStaffed || m.ChartStatusID == (int)Utility.ReferralChartStatus.Partially_Staffed || m.ChartStatusID == (int)Utility.ReferralChartStatus.Restaff) && !m.IsDeleted) .Join(_unitOfWork.ReferralRepository.Get(), t1 => t1.ReferralId, t2 => t2.ReferralId, (t1, t2) => new { t1, t2 }) .AsEnumerable() // Load data to memory .GroupBy(x => x.t2.ReferralId) .Select(group => new { ReferralId = group.Key, ReferralNumber = group.First().t2.ReferralNumber, ConcatenatedValues = string.Join(", ", group.Select(g => g.t1.AssignedStaffName)) }) .ToList();
Key Notes
- Grouping Key: Adjust
GroupBy(item => item.ReferralId)to whatever field you want to group by (e.g.,t2.PatientId). - Distinct Values: Add
.Distinct()to theSelectinsidestring.Joinif you want to avoid duplicate values (e.g.,string.Join(", ", group.Select(g => g.FieldToConcatenate).Distinct())). - Separator: Replace
", "with any separator you need (e.g., "; ", "\n").
内容的提问来源于stack exchange,提问作者Richard Martin

