Python3中如何根据用户多选输入按顺序调用多个函数

Hey there! Let's fix up your code to handle multiple function selections easily, no matter what delimiter the user uses. Here's a revised version that meets your needs, plus a breakdown of the key changes:

Modified Code #

def askUser():
    while True:
        user_input = input("Do you want to run functions? Enter numbers separated by any delimiter (e.g., 1,3 or 2 4): \n")
        # Extract all numeric characters from the input
        choices = []
        for char in user_input:
            if char.isdigit():
                choices.append(int(char))
        
        # Filter out invalid numbers (only keep 1-4)
        valid_choices = [c for c in choices if 0 < c < 5]
        
        if not valid_choices:
            print("Please enter at least one valid number between 1 and 4! Try again.")
            continue
        
        # Notify user about any invalid entries we're ignoring
        invalid_choices = [c for c in choices if c not in range(1, 5)]
        if invalid_choices:
            print(f"Note: Numbers {invalid_choices} are invalid and will be ignored.")
        
        print(f"You entered valid choices: {valid_choices}")
        return valid_choices

def f1():
    print("f1 was called")
def f2():
    print("f2 was called")
def f3():
    print("f3 was called")
def f4():
    print("f4 was called")

# Map numbers to their corresponding functions
mydict = {1: f1, 2: f2, 3: f3, 4: f4}

# Get valid user choices and execute functions in order
selected_choices = askUser()
for choice in selected_choices:
    mydict[choice]()

Key Changes Explained #

• Flexible Input Handling: Instead of forcing a specific delimiter, we extract all numeric characters from the user's input. This works with commas, spaces, semicolons, or even mixed delimiters (like 1 3,2).
• Validation & Feedback: We filter out any numbers outside the 1-4 range and let the user know which entries were invalid. If no valid numbers are entered, we prompt them to try again.
• Sequential Execution: We return a list of valid choices from askUser(), then loop through that list to call each function in the order the user entered them.
• Fixed Original Bug: Your original code tried to call mydict[choice]() before askUser() ran, which would throw an error because choice wasn't defined. We've reordered this to get the choices first, then execute the functions.

内容的提问来源于stack exchange，提问作者Rahul