合并两个多维数组：提取交集键并对对应字段值求和

没问题，我来帮你搞定这个需求！要实现提取两个数组的共同键，并对对应字段求和的功能，咱们可以用PHP的数组函数配合循环来完成，步骤很清晰：

实现步骤 #

• 首先找出两个数组的共同键：用array_intersect_key()函数可以直接获取两个数组都存在的键及其对应元素，或者用array_keys()配合array_intersect()只提取键名。
• 遍历这些共同键，分别对每个键对应的library_count和crypt_count进行求和。
• 将求和后的结果存入新数组。

完整代码示例 #

// 定义第一个数组
$array1 = [
    'Fortitude' => ['library_count' => 0, 'crypt_count' => 7],
    'Obtenebration' => ['library_count' => 6, 'crypt_count' => 11],
    'Dementation' => ['library_count' => 1, 'crypt_count' => 0],
    'Obfuscate' => ['library_count' => 0, 'crypt_count' => 2],
    'Necromancy' => ['library_count' => 9, 'crypt_count' => 2],
    'Celerity' => ['library_count' => 0, 'crypt_count' => 1],
    'Redemption' => ['library_count' => 1, 'crypt_count' => 0],
    'Dominate' => ['library_count' => 19, 'crypt_count' => 2],
    'Auspex' => ['library_count' => 1, 'crypt_count' => 0],
    'Potence' => ['library_count' => 1, 'crypt_count' => 2]
];

// 定义第二个数组
$array2 = [
    'Dominate' => ['library_count' => 19, 'crypt_count' => 7],
    'Celerity' => ['library_count' => 0, 'crypt_count' => 6],
    'Auspex' => ['library_count' => 1, 'crypt_count' => 2],
    'Obtenebration' => ['library_count' => 6, 'crypt_count' => 0],
    'Necromancy' => ['library_count' => 9, 'crypt_count' => 1],
    'Potence' => ['library_count' => 1, 'crypt_count' => 1]
];

// 获取两个数组的共同键
$commonKeys = array_keys(array_intersect_key($array1, $array2));

// 初始化结果数组
$result = [];

// 遍历共同键，计算求和
foreach ($commonKeys as $key) {
    $result[$key] = [
        'library_count' => $array1[$key]['library_count'] + $array2[$key]['library_count'],
        'crypt_count' => $array1[$key]['crypt_count'] + $array2[$key]['crypt_count']
    ];
}

// 输出结果（可以用print_r或者var_dump查看）
print_r($result);

运行结果 #

执行上述代码后，生成的新数组会是这样的：

Array
(
    [Obtenebration] => Array
        (
            [library_count] => 12
            [crypt_count] => 11
        )

    [Necromancy] => Array
        (
            [library_count] => 18
            [crypt_count] => 3
        )

    [Celerity] => Array
        (
            [library_count] => 0
            [crypt_count] => 7
        )

    [Dominate] => Array
        (
            [library_count] => 38
            [crypt_count] => 9
        )

    [Auspex] => Array
        (
            [library_count] => 2
            [crypt_count] => 2
        )

    [Potence] => Array
        (
            [library_count] => 2
            [crypt_count] => 3
        )
)

这个方案逻辑清晰，用了PHP原生数组函数保证效率，而且代码可读性也不错，完全满足你的需求～

内容的提问来源于stack exchange，提问作者PrashJ