如何在索引循环中实现动态步长？特定跳步循环需求咨询

First, let's align with your example output pattern: after printing 9 consecutive numbers using a +1 step, you want to skip 5 numbers (like jumping from 9→15, 23→29) by switching to a +5 step once, then resume the +1 step for the next batch of 9 numbers. Here's the adjusted code:

let count = 0; // Tracks how many numbers we've output in the current sequence
for (let i = 1; i < 101; ) { // We'll handle step increments manually here
    if (count < 9) {
        console.log(i);
        count++;
        i += 1; // Normal +1 step when we're printing numbers
    } else {
        i += 5; // Jump 5 steps to skip the next 5 numbers (e.g., 10→15 skips 10-14)
        count = 0; // Reset count to start a new batch of outputs
    }
}

How This Logic Works: #

• The count variable keeps tabs on how many numbers we've printed since the last skip.
• For each iteration:
  • If we haven't printed 9 numbers yet, we log the current value of i, increment the count, and move to the next number with i +=1.
  • Once we hit 9 printed numbers, we jump 5 steps forward (skipping the next 5 values), reset the count to 0, and start the cycle over.

Alternative Version (Matching Your Original Worded Requirement): #

If your description ("每输出10个数后，将步长从i=i+1改为i=i+5") was the exact rule you want to follow (print 10 numbers then skip), here's that implementation:

let count = 0;
for (let i = 1; i < 101; ) {
    if (count < 10) {
        console.log(i);
        count++;
        i += 1;
    } else {
        i += 5;
        count = 0;
    }
}

This would output 1-10, jump to 15, output 15-24, jump to 29, and so on—strictly following the "10 outputs then +5 step" rule you mentioned.

内容的提问来源于stack exchange，提问作者Mohamed Magdy