Unity与C#入门遇报错：Assets/TextChangeScript.cs(14,29)意外符号错误

嘿，作为Unity新手遇到这种语法错误很正常，我来帮你拆解问题并搞定它！

错误原因分析 #

你碰到的Assets/TextChangeScript.cs(14,29): error CS1525: Unexpected symbol (', expecting ,', ;', or ='错误，根源在这行代码：

yield WaitForSeconds (3);

具体有两个核心问题：

• 协程方法返回类型不对：Start方法默认是void类型，但如果要使用yield实现延迟逻辑，必须把返回类型改成IEnumerator——这是Unity协程的硬性要求。
• yield语法写错了：正确的协程延迟写法应该是yield return new WaitForSeconds(3);，你既漏了return关键字，也没有用new来实例化WaitForSeconds对象。

修正后的完整代码 #

using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using UnityEngine.UI;

public class TextChangeScript : MonoBehaviour {
    public Text m_MyText;
    public Text OtherText;

    // 把返回类型从void改成IEnumerator
    IEnumerator Start() {
        m_MyText.text = "There was once a mother and her child";
        // 修正yield语法，正确创建延迟对象
        yield return new WaitForSeconds(3);
        m_MyText.text = "The mother loved her child very dearly";
    }
}

额外可选方案 #

如果你觉得协程写法有点绕，也可以用Invoke方法实现延迟，这种写法不需要修改Start的返回类型，适合简单的延迟场景：

using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using UnityEngine.UI;

public class TextChangeScript : MonoBehaviour {
    public Text m_MyText;
    public Text OtherText;

    void Start() {
        m_MyText.text = "There was once a mother and her child";
        // 3秒后调用ChangeText方法
        Invoke(nameof(ChangeText), 3);
    }

    void ChangeText() {
        m_MyText.text = "The mother loved her child very dearly";
    }
}

内容的提问来源于stack exchange，提问作者mohammed