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SEC AAER站点批量下载关联文件时的403 Forbidden错误求助

SEC AAER站点批量下载关联文件时的403 Forbidden错误求助

我最近在尝试从SEC的AAER站点批量下载300个关联文件,其中大部分是PDF格式,但也有一些是需要另存为PDF的网页。我正在自学Python网络爬虫,本以为这个任务难度不大,但卡在了下载环节的403错误上,一直没法突破。

目前我已经成功实现了爬取文件链接和对应的4位编号(用来给下载后的文件命名),这部分代码运行正常:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import time
import os
import requests

# Set up Chrome options to allow direct PDF download (for the download step)
download_path = "C:/Users/taylo/Downloads/sec_aaer_downloads"
chrome_options = Options()
chrome_options.add_experimental_option("prefs", {
    "download.default_directory": download_path,  # Specify your preferred download directory
    "download.prompt_for_download": False,  # Disable download prompt
    "plugins.always_open_pdf_externally": True,  # Automatically open PDF in browser
    "safebrowsing.enabled": False,  # Disable Chrome’s safe browsing check that can block downloads
    "profile.default_content_settings.popups": 0  # Disable popups
})

# Set up the webdriver with options
driver = webdriver.Chrome(executable_path="C:/chromedriver/chromedriver", options=chrome_options)

# URLs for pages 1, 2, and 3
urls = [
    "https://www.sec.gov/enforcement-litigation/accounting-auditing-enforcement-releases?page=0",
    "https://www.sec.gov/enforcement-litigation/accounting-auditing-enforcement-releases?page=1",
    "https://www.sec.gov/enforcement-litigation/accounting-auditing-enforcement-releases?page=2"
]

# Initialize an empty list to store the URLs and AAER numbers
pdf_data = []

# Loop through each URL (pages 1, 2, and 3)
for url in urls:
    print(f"Scraping URL: {url}...")
    driver.get(url)

    # Wait for the table rows containing links to be loaded
    WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.XPATH, '//*[@id="block-uswds-sec-content"]/div/div/div[3]/div/table/tbody/tr[1]')))
    
    # Extract the link and AAER number from each row on the current page
    rows = driver.find_elements(By.XPATH, '//*[@id="block-uswds-sec-content"]/div/div/div[3]/div/table/tbody/tr')
    for row in rows:
        try:
            # Extract the link from the first column (PDF link)
            link_element = row.find_element(By.XPATH, './/td[2]/div[1]/a')
            link_href = link_element.get_attribute('href')
            
            # Extract the AAER number from the second column
            aaer_text_element = row.find_element(By.XPATH, './/td[2]/div[2]/span[2]')
            aaer_text = aaer_text_element.text
            aaer_number = aaer_text.split("AAER-")[1].split()[0]  # Extract the number after AAER-

            # Store the data in a list of dictionaries
            pdf_data.append({'link': link_href, 'aaer_number': aaer_number})
        except Exception as e:
            print(f"Error extracting data from row: {e}")

# Print the scraped data (optional for verification)
for entry in pdf_data:
    print(f"Link: {entry['link']}, AAER Number: {entry['aaer_number']}")

但是当我尝试用以下代码进行下载时,始终无法突破403错误,文件根本下载不下来:

import os
import time
import requests

# Set the download path
download_path = "C:/Users/taylo/Downloads/sec_aaer_downloads"
os.makedirs(download_path, exist_ok=True)

# Loop through each entry in the pdf_data list
for entry in pdf_data:
    try:
        # Extract the PDF link and AAER number
        link_href = entry['link']
        aaer_number = entry['aaer_number']

        # Send a GET request to download the PDF
        pdf_response = requests.get(link_href, stream=True, headers={
            "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.124 Safari/537.36"
        })

        # Check if the request was successful
        if pdf_response.status_code == 200:
            # Save the PDF to the download folder, using the AAER number as the filename
            pdf_file_path = os.path.join(download_path, f"{aaer_number}.pdf")
            with open(pdf_file_path, "wb") as pdf_file:
                for chunk in pdf_response.iter_content(chunk_size=8192):
                    pdf_file.write(chunk)
            print(f"Downloaded: {aaer_number}.pdf")
        else:
            print(f"Failed to download the file from {link_href}, status code: {pdf_response.status_code}")
    
    except Exception as e:
        print(f"Error downloading the PDF for AAER {aaer_number}: {e}")

这时候手动下载可能更快,但我更想搞清楚自己哪里出错了。我已经试过设置User-Agent请求头,也试过用Selenium模拟用户点击下载,但都没解决问题。希望能得到大家的建议!

备注:内容来源于stack exchange,提问作者Taylor James

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最近更新时间:2026.04.15 03:20:09