如何结合SORTBY与Echo实现排序时实时输出变量值？

I get what you're asking—when using something like SORTBY (@FileName DESCENDING), you want to see each filename output as it's being handled, instead of waiting for the entire sort to finish before getting any feedback. The core issue here is that most built-in sort functions (like PowerShell's Sort-Object, or similar utilities in other scripting environments) work by first collecting all the items you're sorting. They need the full set to compare and arrange elements in order, so they can't start outputting items until the entire sort operation is complete.

Your attempt with for/do loops makes total sense, but if you were trying to loop through items and sort them one at a time, that won't work because sorting is inherently a batch operation. Here are a couple of practical workarounds depending on your end goal:

1. Show Progress While Collecting Items Before Sorting #

If you just want to confirm things are happening while waiting for the sort to finish, you can output each item as you collect it, then sort the full list afterward. For example, in PowerShell:

# Collect items and echo each one as we gather it
$files = Get-ChildItem | ForEach-Object {
    Write-Host "Collected: $($_.Name)"
    $_
}

# Now sort and output the final sorted list
$files | Sort-Object -Property Name -Descending | ForEach-Object {
    Write-Host "Sorted (descending): $($_.Name)"
}

This way, you get real-time feedback during the collection phase, then see the sorted results once the sort completes.

2. Process Sorted Items Incrementally Once Sorting is Done #

If your main goal is to handle each sorted item as soon as possible (instead of waiting for all processing to end), pipe the sorted output directly into a processing loop. Even though you have to wait for the sort to finish first, once it starts, each item is processed and echoed immediately:

Get-ChildItem | Sort-Object -Property Name -Descending | ForEach-Object {
    # Echo the sorted filename right away, then add your logic
    Write-Host "Processing sorted file: $($_.Name)"
    # Insert your custom processing here
}

In this case, once the sort completes, you'll see each filename printed one after another without waiting for all processing to finish.

Why Your For/Do Loop Didn't Work #

If you tried looping through items and sorting them individually, that won't produce a sorted list—you're just sorting single items (which does nothing) and outputting them in their original order. Sorting requires comparing multiple elements against each other, so you can't do it incrementally on individual items.

The key takeaway: Sorting inherently needs a full set of items to work with, so you can't get truly incremental output during the sort itself. But you can add visibility during collection or process sorted items the moment the sort wraps up.

内容的提问来源于stack exchange，提问作者scot