Oracle中如何利用集合使函数返回第2个和第4个值？

No problem at all—let's get your function returning both the 2nd and 4th values like you need. First, a quick critical note: most programming languages use 0-based indexing, so the 2nd element sits at index 1 and the 4th at index 3 (that’s likely why you were only pulling the 4th value before).

Example Fix in Python #

Say your original function looked like this (only returning the 4th element):

def get_target_values(input_list):
    # Only returns the 4th element (index 3)
    return input_list[3]

To return both values, just adjust the return statement to include both indices. Python lets you return multiple values directly as a tuple:

def get_target_values(input_list):
    # Return 2nd element (index 1) and 4th element (index 3)
    return input_list[1], input_list[3]

When you call this function, capture both values like so:

my_list = [10, 42, 30, 46]
second_val, fourth_val = get_target_values(my_list)
print(second_val)  # Output: 42
print(fourth_val)  # Output: 46

Example Fix in JavaScript #

If you’re working with JS, the approach is similar—return an array containing the two elements:

function getTargetValues(arr) {
    // Return 2nd element (index 1) and 4th element (index 3)
    return [arr[1], arr[3]];
}

// Usage:
const myArr = [10, 42, 30, 46];
const [secondVal, fourthVal] = getTargetValues(myArr);
console.log(secondVal); // 42
console.log(fourthVal); // 46

Quick Reminder #

Always confirm your language’s indexing rule—0-based means the nth element lives at index n-1. By including both target indices in your return statement, you’ll get exactly the two values you’re expecting.

内容的提问来源于stack exchange，提问作者virendra suhane