TensorFlow中Adagrad优化器工作原理及参数δ对应设置咨询
Hey Garrett, let’s tackle your questions one by one—they’re super relevant for anyone diving into adaptive optimizers!
How Does TensorFlow’s AdagradOptimizer Work?
At its core, Adagrad is designed to give adaptive learning rates to each parameter in your model. Here’s the breakdown:
- For each parameter, it maintains an accumulator that sums the squares of all past gradients for that parameter.
- When updating the parameter, it scales the learning rate by the square root of this accumulator (plus a small value to avoid division by zero). The formula (aligned with the original paper) looks like this:
Where:θ_{t+1} = θ_t - (η / sqrt(G_t + δ)) * g_tηis the base learning rateG_tis the sum of squared gradients up to steptδis a small epsilon to prevent division by zerog_tis the current gradient for the parameter
In TensorFlow’s implementation, AdagradOptimizer follows this logic exactly—though the naming of some parameters differs from the paper, which brings us to your next question.
δ vs. initial_accumulator_value: What’s the Connection?
You’re right to notice the discrepancy: the original paper mentions a δ parameter, but TensorFlow’s constructor only has initial_accumulator_value. Here’s why:
- In the paper,
G_tstarts at 0, andδis added toG_twhen calculating the learning rate scale. This ensures we never divide by zero, even if no gradients have been accumulated yet. - TensorFlow rolls these two concepts into one:
initial_accumulator_valuesets the starting value of the accumulatorG_0. Instead of addingδtoG_tlater, TensorFlow initializesG_0to a non-zero value (default 0.1) to avoid division by zero from the get-go.
So TensorFlow’s initial_accumulator_value effectively serves the same purpose as the paper’s δ—it’s a safeguard against division by zero. The default 0.1 is a conservative choice, but it’s not the only option.
Is Setting initial_accumulator_value to 0 Appropriate?
Short answer: It’s possible, but risky unless you’re certain about your model’s behavior. Here’s the detail:
- If you set
initial_accumulator_value=0, you’re mimicking the paper’s initialG_0=0—but you lose the built-in safeguard against division by zero. If any parameter has a gradient of 0 for all early steps (or ever), its accumulator will stay at 0, leading to a division by zero error (NaN values in your model). - The paper recommends
δas a tiny positive number (like 1e-8), not 0. So if you want to align closely with the paper, a better choice is to setinitial_accumulator_value=1e-8instead of 0. This keeps the division-safe behavior while staying true to the paper’s intent. - The TensorFlow default of 0.1 is a more robust choice for general use, especially if you’re working with sparse gradients (common in NLP or recommendation systems) where some parameters might see no updates early on.
Final Takeaway
Stick to a tiny positive value (like 1e-8) if you want to follow the paper closely, or keep the default 0.1 for safer, out-of-the-box performance. Avoid setting it to 0 unless you’ve verified none of your parameters will have zero gradients for extended periods.
内容的提问来源于stack exchange,提问作者Garrett

