在CMS编辑器环境下，JavaScript是否存在替代<、>的大于小于判断方式？

Absolutely, there are several practical ways to handle numerical (and even string) comparisons without using the literal < or > operators—exactly what you need to get past that CMS editor's strict HTML validation. Here are my go-to solutions:

1. Use Math.max() / Math.min() for Numerical Checks #

This is one of the most readable approaches. The idea is simple: if a is the maximum of a and b, then a must be greater than b; similarly, if a is the minimum, it's less than b.

// Check if a > b
const isGreater = Math.max(a, b) === a;

// Check if a < b
const isLess = Math.min(a, b) === a;

// Bonus: Check if a >= b (max equals a OR they're equal)
const isGreaterOrEqual = Math.max(a, b) === a;

// Check if a <= b
const isLessOrEqual = Math.min(a, b) === a;

2. Leverage Math.sign() for Precise Sign Checks #

Math.sign() returns 1 for positive numbers, -1 for negative numbers, and 0 for zero. Subtract your values and check the sign to avoid </> entirely.

// Check if a > b (a - b is positive)
const isGreater = Math.sign(a - b) === 1;

// Check if a < b (a - b is negative)
const isLess = Math.sign(a - b) === -1;

// Check if a === b
const isEqual = Math.sign(a - b) === 0;

Note: Math.sign() is supported in all modern browsers and Node.js 0.12+. For older environments, you could polyfill it (just ensure your polyfill doesn’t rely on </> if you need to keep avoiding them).

3. Bitwise Shifts (For 32-Bit Integers Only) #

This is a niche trick, useful only if you’re working strictly with 32-bit integers. When you subtract two numbers and right-shift by 31 bits, you get -1 if the result is negative (meaning a < b) and 0 if it’s non-negative.

// Check if a < b (only works for 32-bit integers)
const isLess = (a - b) >> 31 === -1;

// Check if a > b (reverse the subtraction)
const isGreater = (b - a) >> 31 === -1;

⚠️ Caveat: This fails for floats or numbers outside the 32-bit integer range (e.g., 2**31 or higher), so use this only if you’re certain about your input types.

4. String Comparisons with localeCompare() #

If you’re working with string lexicographical comparisons, localeCompare() returns 1 (a comes after b), -1 (a comes before b), or 0 (equal)—no </> needed.

// Check if string a is "greater than" string b (dictionary order)
const isStrGreater = a.localeCompare(b) === 1;

// Check if string a is "less than" string b
const isStrLess = a.localeCompare(b) === -1;

This is especially handy because string comparisons with </> can be inconsistent across locales, and localeCompare() lets you add locale-specific rules if needed.

内容的提问来源于stack exchange，提问作者omega