如何以最简洁地道的方式向数组列表添加元素?能否完全移除代码中的循环?
Hey there! Let's figure out how to generate your target list [[0, -1], [1, 0], [2, 1]] without writing any explicit loops in your code. Here are a couple of clean, loop-free approaches in Python:
Approach 1: Using zip() + map()
This method leverages built-in functions to handle pairing and conversion without manual loop logic:
result = list(map(list, zip(range(3), range(-1, 2))))
range(3)generates the sequence0, 1, 2range(-1, 2)generates-1, 0, 1zip()pairs corresponding elements from the two ranges into tuplesmap(list, ...)converts each tuple to a list- Wrapping the whole thing in
list()gives you the final nested list.
Approach 2: List Comprehension (Implicit Loop)
If you’re okay with Python’s implicit loop syntax sugar, this is an even more concise and Pythonic option:
result = [[i, i-1] for i in range(3)]
This directly constructs each sublist by calculating i and i-1 for every value in range(3)—no manual for/while loops in your code at all.
Both approaches will output exactly the list you need, with zero hand-written loops.
内容的提问来源于stack exchange,提问作者John Difool
相关产品推荐
相关产品推荐

