Python新手遇ValueError：无法将'26.02.2018'转为十进制整数求助

Hey there! Let's break down why you're hitting this error and get your script back on track quickly.

What's Causing the Error? #

That error happens because you’re trying to use int() on the string '26.02.2018'—and Python can’t convert a date-formatted string (with dots separating day/month/year) into an integer directly. The int() function only works on strings that are pure whole numbers (like '26' or '2018'), not strings with non-digit separators or mixed date components.

Solutions Based on Your Goal #

Depending on what you want to do with that date, here are tailored fixes:

1. Extract Individual Date Parts as Integers

If you just need the day, month, and year as separate integers, split the string first then convert each segment:

date_str = '26.02.2018'
# Split the string by '.' and convert each part to int
day, month, year = map(int, date_str.split('.'))
print(f"Day: {day}, Month: {month}, Year: {year}")
# Output: Day: 26, Month: 2, Year: 2018

2. Convert to a Proper Date Object (Recommended)

If you plan to do date-related operations (like calculating differences, reformatting, etc.), use Python’s built-in datetime module to parse the string into a usable date object:

from datetime import datetime

date_str = '26.02.2018'
# The format string '%d.%m.%Y' matches your DD.MM.YYYY input
date_object = datetime.strptime(date_str, '%d.%m.%Y')
print(f"Parsed date: {date_object}")
# Output: 2018-02-26 00:00:00

# If you need an integer (like a Unix timestamp), convert it like this:
timestamp = int(date_object.timestamp())
print(f"Unix timestamp: {timestamp}")

3. Add Error Handling for Robustness

If your script deals with user input or external data, add a try-except block to catch invalid date formats gracefully:

from datetime import datetime

def safe_parse_date(date_input):
    try:
        return datetime.strptime(date_input, '%d.%m.%Y')
    except ValueError:
        print(f"Oops! '{date_input}' isn't a valid DD.MM.YYYY date. Double-check the format.")
        return None

# Test the function
my_date = safe_parse_date('26.02.2018')
if my_date:
    print(f"Success! Formatted date: {my_date.strftime('%B %d, %Y')}")
# Output: Success! Formatted date: February 26, 2018

内容的提问来源于stack exchange，提问作者RelaxxxedMato