编程新手求助：如何让cout输出字符串中指定字符的下一个字符？

Hey there! Let's get this sorted out for you. It sounds like you're probably just outputting the target character itself instead of the one right after it—super easy mistake to make when you're starting out!

Here's a step-by-step breakdown of how to fix this:

• First, you need to find the position of your target character in the string. You can use the find() method built into C++ strings for this.
• Next, make sure the character was actually found (so you don't try to access an invalid position) and that there is a next character (i.e., the target isn't the last character in the string).
• Finally, grab the character at the position right after the target and output it with cout.

Here's a complete working example code:

#include <iostream>
#include <string>

using namespace std;

int main() {
    string my_str = "Hello World";
    char target_char = 'e';

    // Find the position of the target character
    size_t char_pos = my_str.find(target_char);

    // Check if we found the character AND there's a next character
    if (char_pos != string::npos && char_pos + 1 < my_str.length()) {
        char next_char = my_str[char_pos + 1];
        cout << "The next character is '" << next_char << "'" << endl;
    } else {
        // Handle cases where the character isn't found or has no next character
        cout << "Oops! Either the target character wasn't found, or it's the last character in the string." << endl;
    }

    return 0;
}

Key Notes: #

• my_str.find(target_char) returns the index of the first occurrence of the target character. If it can't find the character, it returns string::npos (a special value meaning "no position").
• We check char_pos + 1 < my_str.length() to avoid trying to access a position that doesn't exist (like if your target was 'd' in "Hello World", there's no character after it).
• The mistake you were likely making was using my_str[char_pos] instead of my_str[char_pos + 1] in your cout statement—hence why you were getting the same character back!

内容的提问来源于stack exchange，提问作者Benny