使用Python辅助函数：循环排数与无青少年值求和实现

Got it, let's break this down with clean, modular code as requested—splitting the logic into two functions avoids repeating the teen-value check multiple times, which keeps things maintainable.

Step 1: The fix_teen Helper Function #

First, we'll build the helper that handles the teen-value rule. It takes an integer n and returns 0 if n is a qualifying teen value (13-19 inclusive, excluding 15 and 16), otherwise it returns the original number.

def fix_teen(n):
    # Check if n falls in the teen range but isn't 15 or 16
    if 13 <= n <= 19 and n not in (15, 16):
        return 0
    return n

Step 2: The no_teen_sum Main Function #

The main function is simple from here—we just apply the fix_teen helper to each input integer and sum up the corrected values.

def no_teen_sum(a, b, c):
    return fix_teen(a) + fix_teen(b) + fix_teen(c)

Test It With Examples #

Let's run a few test cases to confirm it works as expected:

• no_teen_sum(13, 15, 19) returns 0 + 15 + 0 = 15
• no_teen_sum(2, 16, 17) returns 2 + 16 + 0 = 18
• no_teen_sum(14, 15, 16) returns 0 + 15 + 16 = 31

This modular approach means if you ever need to tweak the teen-value rules later, you only have to update the fix_teen function instead of editing three separate checks!

内容的提问来源于stack exchange，提问作者Samir Tendulkar