栈内容对比项目函数报错求助:两类编译错误排查
Hey there! Let's break down these two errors step by step and get your stack comparison project back on track:
1. "Expression must have class type" when calling B.myCharacters.empty()
This error almost always means you're using the dot operator (.) to access a member on something that isn't a class/struct instance—most commonly, a pointer.
- What's happening: If
Bwas declared as a pointer to your stack class (likeStack* B;instead ofStack B;), the dot operator won't work here. Pointers require the arrow operator (->) to access their members. - Quick fix: If
Bis a pointer, change the call toB->myCharacters.empty(). If you intendedBto be a direct instance of the class, double-check your variable declaration to make sure it's not accidentally a pointer.
2. "no operator '==' matched these operands" when using B == B.myCharacters
This error comes from trying to compare two incompatible types:
Bis an instance (or pointer) of your full stack classB.myCharactersis the internal stack member inside that class (like astd::stack<char>or custom stack type)
You can't compare the entire class object to one of its internal members directly—your teacher's provided header almost certainly doesn't define an operator for that mismatch.
Fix options to choose from:
- Compare the stack members directly: If your goal is to check if two stack objects have identical contents, compare their
myCharactersmembers against each other. For example, if you're comparing objectsAandB, useA.myCharacters == B.myCharacters(orA->myCharacters == B->myCharactersif they're pointers). - Overload the
==operator for your class (if allowed): If you want to write clean code likeA == Bto compare the stacks, you can define an overloaded equality operator for your class. Here's a quick example:
Note: If you can't modify the teacher-provided header, this might not be an option—stick to the first fix in that case.bool operator==(const YourStackClassName& other) const { return this->myCharacters == other.myCharacters; }
Since you can't alter the provided header or driver, focusing on adjusting how you access the stack members and comparing matching types should resolve both issues smoothly.
内容的提问来源于stack exchange,提问作者Jeffrey Smith

