Hey there! Let's sort out that syntax error you're running into. The issue is simple but easy to miss—you're missing a comma between the key-value pairs in your array.

In PHP, when you define an associative array with multiple entries, every key-value pair (except the last one) needs to be separated by a comma. In your line 21 code:

exit (json_encode(array("status" => 1 "msg" => 'Please check your email inbox!')));

Right after "status" => 1, there's no comma to tell PHP that we're moving to the next array element ("msg"). The parser gets confused and throws that unexpected string error because it wasn't expecting another key declaration without a separator first.

Here's the corrected code with the missing comma added:

exit(json_encode(array("status" => 1, "msg" => 'Please check your email inbox!')));

A quick extra tip: While PHP allows mixing single and double quotes for strings here, it's a good practice to keep them consistent (e.g., use double quotes for both keys and values) to make your code cleaner and easier to maintain down the line.

内容的提问来源于stack exchange，提问作者CD6554