如何从目录中使用glob获取两类同日期前缀数据文件的独立文件名列表？

I get it, you need two distinct lists: one for your regular date-named .dat files, and another for the ones with the _patients suffix. Here's exactly how to do it with glob:

1. Fetch Regular Data Files (e.g., 2018-01-02.dat) #

Use a glob pattern that matches the fixed YYYY-MM-DD date format followed directly by .dat.

For a flexible pattern that works for any valid date (using ? to match any single character in the date positions):

import glob

regular_files = glob.glob("????-??-??.dat")

For a stricter pattern that only accepts digits in the date fields (using character classes):

regular_files = glob.glob("[0-9][0-9][0-9][0-9]-[0-9][0-9]-[0-9][0-9].dat")

2. Fetch Patient Data Files (e.g., 2018-01-02_patients.dat) #

Extend the previous pattern to include the _patients suffix right before .dat:

Flexible version:

patient_files = glob.glob("????-??-??_patients.dat")

Strict digit-only version:

patient_files = glob.glob("[0-9][0-9][0-9][0-9]-[0-9][0-9]-[0-9][0-9]_patients.dat")

Quick Notes #

• If your files live in a subdirectory, prepend the path to the pattern (e.g., "./data/????-??-??.dat").
• To search recursively through nested folders, add **/ at the start of the pattern and use the recursive=True flag: glob.glob("**/????-??-??.dat", recursive=True).
• These patterns guarantee no overlap between the two lists—since the _patients suffix is unique to the second file type, you’ll get clean, separate results every time.

Content of the question originates from Stack Exchange, question author Ted