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求解随机变量x∈(6,14)的概率:已知P(x>6)与P(x<16)如何应用?

Calculating P(6 < x < 14) with Given Probabilities

Hey there, let's walk through why your initial approach didn't work and what's needed to solve this properly.

First, let's clarify what we can derive from the given values:

  • P(x > 6) = 0.9095 → This means P(x ≤ 6) = 1 - 0.9095 = 0.0905 (since total probability across all outcomes equals 1)
  • P(x < 16) = 0.8360 → This means P(x ≥ 16) = 1 - 0.8360 = 0.1640

Your attempt to divide these probabilities doesn't apply here—probability division is only used for conditional probability scenarios (like calculating P(A|B) = P(A∩B)/P(B)), which isn't what we're trying to find with this range probability.

The Gap in Existing Information

To compute P(6 < x < 14), we need to calculate P(x < 14) - P(x ≤ 6)—this subtracts the probability of x being ≤6 from the probability of x being <14 to isolate the middle range we care about.

The problem is: we don't have P(x < 14), and without knowing the underlying distribution of x (e.g., normal, uniform, exponential), we can't infer this value from the two given probabilities alone.

Example: If x Follows a Normal Distribution

If we assume x is normally distributed (a common real-world scenario), we can use the known probabilities to estimate the mean (μ) and standard deviation (σ), then calculate the desired range:

  1. Convert the known probabilities to Z-scores using the inverse normal distribution:
    • P(x ≤ 6) = 0.0905 corresponds to a Z-score of ~-1.33 (the 9.05th percentile of the standard normal distribution)
    • P(x < 16) = 0.8360 corresponds to a Z-score of ~0.98 (the 83.6th percentile of the standard normal distribution)
  2. Set up equations for Z-scores:
    (6 - μ)/σ = -1.33
    (16 - μ)/σ = 0.98
    
  3. Solve for μ and σ:
    Subtract the first equation from the second: (16-6)/σ = 0.98 - (-1.33) → 10/σ = 2.31 → σ ≈ 4.33
    Plug σ back into the first equation: 6 - μ = -1.33*4.33 → μ ≈ 6 + 5.76 = 11.76
  4. Calculate the Z-score for x=14: (14 - 11.76)/4.33 ≈ 0.52
  5. Find P(x < 14) by looking up the Z-score 0.52 in the standard normal table (~0.6985)
  6. Finally, P(6 < x < 14) = 0.6985 - 0.0905 = 0.608

Key Takeaway

Without knowing the distribution of x, or having an additional probability value (like P(x < 14)), you can't compute the exact probability you're looking for. The critical missing piece is information about how x is distributed.

内容的提问来源于stack exchange,提问作者Lara Jane

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最近更新时间:2026.05.19 09:15:13