执行脚本出现error parsing getopt parameters错误，请求排查代码问题

Hey Firas, sorry you hit this roadblock with your script! Since you haven't shared the full code of myscript.sh, I can break down the most common reasons this getopt parsing error happens and what you’re likely missing:

• Missing or incorrect long option definitions in getopt
  If your script uses long options like --certtype, --password, and --commonname, you need to explicitly declare them in the getopt call using the --long flag. Each option that requires a value (like all yours do) should end with a colon :. For example, your getopt line should look something like this:

  OPTIONS=$(getopt -o "" --long certtype:,password:,commonname: -n "$0" -- "$@")
  

  If any of these options are missing from the --long list, or you forgot the colon for options that take arguments, getopt will throw a parsing error.

• Skipping the eval set -- step
  After running getopt, you need to reassign the parsed output back to your script’s positional parameters. This step ensures your subsequent option-parsing logic can read the parameters correctly. You’ll need a line like:

  eval set -- "$OPTIONS"
  

  Without this, your script won’t properly interpret the parsed options, leading to errors.

• Unquoted variables in the getopt call
  Always wrap "$@" in double quotes when passing arguments to getopt—this preserves spaces and special characters in your input values. If you wrote getopt ... -- $@ instead of getopt ... -- "$@", that could break parameter parsing.

Example Working Getopt Snippet #

Here’s a quick example of how this should look in your script to handle your specified options:

#!/bin/bash

# Parse command line options
OPTIONS=$(getopt -o "" --long certtype:,password:,commonname: -n "$0" -- "$@")
if [ $? -ne 0 ]; then
    echo "Error parsing parameters!" >&2
    exit 1
fi

# Reset positional parameters to parsed options
eval set -- "$OPTIONS"

# Process each option
while true; do
    case "$1" in
        --certtype)
            CERT_TYPE="$2"
            shift 2
            ;;
        --password)
            PASSWORD="$2"
            shift 2
            ;;
        --commonname)
            COMMON_NAME="$2"
            shift 2
            ;;
        --)
            shift
            break
            ;;
        *)
            echo "Unknown option: $1" >&2
            exit 1
            ;;
    esac
done

# Rest of your script logic here...

Double-check your script against these points—chances are one of these pieces is missing. If you can share more of your script code, I can give an even more targeted fix!

内容的提问来源于stack exchange，提问作者F. K.