如何基于到店商品序列，按指定规则展示状态（OK、NOT）

Hey there, let's walk through how to solve this status check problem step by step. The core logic centers on counting how many BULBS arrive before the first FRION in your inbound sequence, then applying your defined rules to output the correct status.

Core Rule Recap #

Let's restate the rules clearly to avoid confusion:

• If the number of BULBS received before the first FRION is ≤ 4 → Status = OK
• If the number of BULBS received before the first FRION is ≥ 5 → Status = NOT

Example Scenarios #

Let's test this with real-world sequence examples to make it concrete:

1. Sequence: ["BULBS", "BULBS", "FRION", "BULBS"] → BULBS count before FRION: 2 → Status: OK
2. Sequence: ["BULBS", "BULBS", "BULBS", "BULBS", "BULBS", "FRION"] → BULBS count before FRION: 5 → Status: NOT
3. Sequence: ["FRION", "BULBS", "BULBS"] → BULBS count before FRION: 0 → Status: OK

Code Implementation (Python Example) #

Here's a straightforward function that takes your inbound sequence and returns the correct status. It stops processing as soon as it hits the first FRION to keep things efficient:

def get_inbound_status(inbound_sequence):
    bulbs_before_frion = 0
    for item in inbound_sequence:
        if item == "FRION":
            # Trigger the status check as soon as we encounter the first FRION
            return "OK" if bulbs_before_frion <= 4 else "NOT"
        elif item == "BULBS":
            bulbs_before_frion += 1
    # Edge case: No FRION found in the sequence (adjust this return value if needed)
    return "NO_FRION_DETECTED"

Test the function with our examples:

print(get_inbound_status(["BULBS", "BULBS", "FRION", "BULBS"]))  # Output: OK
print(get_inbound_status(["BULBS"]*5 + ["FRION"]))  # Output: NOT
print(get_inbound_status(["FRION", "BULBS"]))  # Output: OK

Edge Cases to Keep in Mind #

• Multiple FRION entries: The rule only cares about the first occurrence of FRION. Any BULBS that arrive after the first FRION don't impact the status.
• No FRION in the sequence: The original rule doesn't cover this scenario, so the function returns a custom fallback status—you can adjust this to fit your workflow needs.

内容的提问来源于stack exchange，提问作者dran