Linux脚本开发：读取路径行从Zip复制文件至目标路径

Hey there! Let's put together a simple, robust script that does exactly what you need—whether you're processing a list of files from an input text or copying a single file on the fly. I'll walk through each part so you understand what's going on, no confusing jargon included.

Step 1: The Complete Script #

First, save this as copy_from_zip.sh (feel free to pick a name that makes sense to you):

#!/bin/bash

# --------------------------
# CONFIGURE THIS FIRST!
# Replace with your actual zip file's full path
ZIP_FILE="/full/path/to/your/target_files.zip"
# --------------------------

# Handle different input scenarios
if [ $# -eq 1 ]; then
    # Case 1: Process all lines from an input text file
    INPUT_FILE="$1"

    # Check if the input file exists before proceeding
    if [ ! -f "$INPUT_FILE" ]; then
        echo "❌ Error: Input file '$INPUT_FILE' doesn't exist!"
        exit 1
    fi

    # Read each line of the input file
    while read -r src_dst_line; do
        # Skip empty lines to avoid errors
        [ -z "$src_dst_line" ] && continue

        # Split the line into source path (from inside the zip) and destination path
        # This works even if the destination path has spaces!
        src_path=$(echo "$src_dst_line" | awk '{print $1}')
        dst_path=$(echo "$src_dst_line" | awk '{for(i=2; i<=NF; i++) printf "%s ", $i; print ""}' | xargs)

        # Create the destination directory if it doesn't exist
        mkdir -p "$(dirname "$dst_path")"

        # Extract the file from the zip and write it to the destination
        if unzip -p "$ZIP_FILE" "$src_path" > "$dst_path"; then
            echo "✅ Copied '$src_path' to '$dst_path'"
        else
            echo "❌ Failed to copy '$src_path' to '$dst_path'"
        fi
    done < "$INPUT_FILE"

elif [ $# -eq 2 ]; then
    # Case 2: Copy a single file directly via command line arguments
    src_path="$1"
    dst_path="$2"

    # Create destination directory if needed
    mkdir -p "$(dirname "$dst_path")"

    # Extract and copy the file
    if unzip -p "$ZIP_FILE" "$src_path" > "$dst_path"; then
        echo "✅ Copied '$src_path' to '$dst_path'"
    else
        echo "❌ Failed to copy '$src_path' to '$dst_path'"
    fi

else
    # Show usage instructions if the wrong number of arguments is passed
    echo "Usage:"
    echo "  $ ./copy_from_zip.sh <input_file.txt>  # Process all lines in the input file"
    echo "  $ ./copy_from_zip.sh <zip_internal_path> <destination_path>  # Copy a single file"
    exit 1
fi

Step 2: Make the Script Executable #

Run this command in your terminal to give the script permission to run:

chmod +x copy_from_zip.sh

Step 3: How to Use It #

Option 1: Process an Input File #

If your input file (e.g., file_list.txt) looks like this:

docs/report.pdf /home/user/documents/my_report.pdf
images/photo.jpg /home/user/pictures/vacation photo.jpg
data/metrics.csv /home/user/analytics/monthly_data.csv

Run the script like this:

./copy_from_zip.sh file_list.txt

Option 2: Copy a Single File Directly #

Just pass the path inside the zip and your destination path (wrap paths with spaces in quotes):

./copy_from_zip.sh "docs/report.pdf" "/home/user/documents/my_report.pdf"

Key Tips for Newbies #

• Update the Zip Path: Don't forget to change the ZIP_FILE variable at the top to point to your actual zip file (use the full path to avoid "file not found" errors!).
• Paths with Spaces: If your file paths have spaces, wrap them in double quotes in your input file or when passing them as arguments—the script is set up to handle this.
• Automatic Directory Creation: The script will make any missing folders for your destination path, so you don't have to run mkdir manually.
• Error Feedback: You'll get clear success/failure messages for each file, so you know exactly what worked and what didn't.

内容的提问来源于stack exchange，提问作者obidyne