如何进行三次多项式因式分解?求解$m^3 - 2m + 1$的分解方法
m³ - 2m + 1 Hey there! Let's walk through exactly how to factor this cubic polynomial step by step—you'll see it's all about using a few key tricks that work for most cubics with rational roots.
Step 1: Use the Rational Root Theorem to Find a Linear Factor
First, let's recall the Rational Root Theorem: for a polynomial like $a_nx^n + ... + a_1x + a_0$, any rational root $\frac{p}{q}$ must have $p$ as a factor of the constant term ($a_0$) and $q$ as a factor of the leading coefficient ($a_n$).
For m³ - 2m + 1:
- Constant term is 1, so possible $p$ values are ±1
- Leading coefficient is 1, so possible $q$ values are ±1
- That means our only possible rational roots are 1 and -1
Now test these values in the polynomial:
- When $m=1$: $1³ - 2(1) + 1 = 1 - 2 + 1 = 0$ → Bingo! $m=1$ is a root, so $(m - 1)$ is a factor of the polynomial.
Step 2: Factor Out the Linear Term (Two Methods)
Now that we know $(m-1)$ is a factor, we need to find the remaining quadratic factor. Here are two easy ways to do this:
Method 1: Polynomial Long Division
Divide m³ - 2m + 1 by $(m - 1)$:
m² + m - 1 _______________ m - 1 | m³ + 0m² - 2m + 1 - (m³ - m²) ----------- m² - 2m - (m² - m) --------- -m + 1 - (-m + 1) --------- 0
The quotient is m² + m - 1, which can't be factored further over the integers (since its discriminant $1² - 4(1)(-1) = 5$ isn't a perfect square).
Method 2: Grouping by Rearranging Terms
If you don't want to do long division, you can rearrange the polynomial to group terms with $(m-1)$ as a common factor:
Start with m³ - 2m + 1 → add and subtract $m²$ (this doesn't change the value, just lets us group):
m³ - m² + m² - 2m + 1
Now split into groups:
(m³ - m²) + (m² - 2m + 1)
Factor each group:
m²(m - 1) + (m - 1)²
Now factor out $(m - 1)$ from both terms:
(m - 1)(m² + (m - 1)) = (m - 1)(m² + m - 1)
Perfect—same result as the division method!
Final Result
Putting it all together, we get:m³ - 2m + 1 = (m - 1)(m² + m - 1)
Quick Recap for Future Cubics
- Use the Rational Root Theorem to test possible rational roots.
- Once you find a root $r$, $(x - r)$ is a factor.
- Use polynomial division or grouping to find the remaining quadratic factor.
- Check if the quadratic can be factored further (using discriminant or trial and error).
内容的提问来源于stack exchange,提问作者kondz1v

