如何用Python-Selenium每10秒刷新页面检查Jenkins任务成功/失败状态？

Hey there! Let's fix up your script to properly monitor your Jenkins task's completion status. First, let's break down the issues with your current code, then walk through an optimized version.

Core Issues in Your Current Script #

• Broken Logic Flow: Your else clause only ties to the second if failure check. That means if the script detects SUCCESS, it will still trigger the else block and refresh the page—definitely not what you want.
• No Continuous Monitoring: The script only runs one check; if it doesn't find a result, it refreshes once and stops. It won't keep checking until the Jenkins task finishes.
• No Timeout Safeguard: Since your task runs 15-30 minutes, without a timeout the script could loop infinitely if something goes wrong.
• Refresh Interval Mismatch: You wanted a 10-second refresh, but the script uses time.sleep(5).

Optimized Full Script #

import time
import re
from selenium import webdriver

# Initialize your browser driver (adjust for Chrome/Firefox/etc.)
driver = webdriver.Chrome()
driver.get("YOUR_JENKINS_TASK_PAGE_URL")

# Set max wait time (30 mins = 1800 secs, add a small buffer)
max_wait_seconds = 1800
start_timestamp = time.time()

# Loop until we get a result or hit the timeout
while True:
    # Check if we've exceeded the max wait time
    elapsed_time = time.time() - start_timestamp
    if elapsed_time > max_wait_seconds:
        print("Timeout reached: Jenkins task ran longer than 30 minutes")
        break

    page_source = driver.page_source
    # Search for both statuses
    success_found = re.search(r'Finished: SUCCESS', page_source)
    failure_found = re.search(r'Finished: FAILURE', page_source)

    if success_found:
        print('✅ Task completed successfully: SUCCESS')
        break
    elif failure_found:
        print('❌ Task failed: FAILURE')
        break
    else:
        print(f"Still waiting... Elapsed time: {int(elapsed_time)}s. Refreshing in 10s.")
        time.sleep(10)
        driver.refresh()

# Clean up: close the browser to avoid leftover processes
driver.quit()

Key Improvements Explained #

• Correct Logic Structure: Uses if-elif-else to ensure we only refresh when neither status is found.
• Continuous Monitoring: The while True loop keeps checking until we get a success/failure or hit the timeout.
• Timeout Protection: Prevents infinite loops by stopping the script after 30 minutes.
• Matching Refresh Interval: Updated to time.sleep(10) to align with your requirement.
• Resource Cleanup: driver.quit() ensures the browser closes properly after the script finishes.

Bonus: More Efficient Dynamic Waiting #

If your Jenkins page loads status updates dynamically, using Selenium's explicit waits is more efficient than checking the full page source repeatedly. Here's how you can adjust the loop:

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By

# Replace the loop logic above with this
while True:
    elapsed_time = time.time() - start_timestamp
    if elapsed_time > max_wait_seconds:
        print("Timeout reached: Jenkins task ran longer than 30 minutes")
        break

    try:
        # Wait up to 10 seconds for the "Finished:" status element to appear
        status_element = WebDriverWait(driver, 10).until(
            EC.presence_of_element_located((By.XPATH, "//*[contains(text(), 'Finished:')]"))
        )
        if "SUCCESS" in status_element.text:
            print('✅ Task completed successfully: SUCCESS')
        else:
            print('❌ Task failed: FAILURE')
        break
    except:
        # If the status doesn't appear in 10s, refresh and try again
        print(f"Still waiting... Elapsed time: {int(elapsed_time)}s. Refreshing now.")
        driver.refresh()

This approach targets the exact status element instead of scanning the entire page source, making it faster and more reliable.

内容的提问来源于stack exchange，提问作者Sidharth Gokul