使用GeoFirestore查询附近位置时始终返回空对象{}的问题排查

数据老陈

2026-11-2

Firebase Functions 周边点位查询接口空返回问题

已编写两个云函数实现核心功能：

支持用户完成位置签到操作
基于给定坐标查询周边点位信息

签到功能实现（运行正常）

签到功能的代码逻辑如下：

.https.onRequest(async(request, response) =>{
     const uid = request.query.uid
     const cat = request.query.cat
     const addr = request.query.add
     const name = request.query.name
     const long = Number(request.query.long)
     const lat = Number(request.query.lat)
     const gpoint = new admin.firestore.GeoPoint(lat,long)
     const db = admin.firestore()
     const tstamp = Date.now()
     const adata = {
        createdate: tstamp,
        checkins: 1,
        lastcheckin: tstamp,
        status: null,
        createdby: uid,
        category: cat,
        address: addr,
        name: name,
        lat: lat,
        long: long,
        gid: null,
        g: {
          coordinates: gpoint,
        },
       }
      await db.collection('places').add(adata)
      response.send('OK')
  })

该功能运行无异常，存储的点位数据结构符合设计预期。

周边点位查询功能实现

基于GPS坐标查询附近点位的功能代码逻辑如下：

.https.onRequest(async(request, response) =>{
     const long= Number(request.query.long)
     const lat = Number(request.query.lat)
     const GeoFirestore = require('geofirestore').GeoFirestore
     const database = admin.firestore();
    const geofirestore = new GeoFirestore(database);
    const Geo = geofirestore.collection('places')
    const query = Geo.near({center: new admin.firestore.GeoPoint(lat,long), radius: 10 })
     query.get()
      .then((snapshot: { data: () => any }) =>{
       // const data =(snapshot.data())
        response.send(snapshot.data())
     })
       .catch((error: any) => {
           console.log(error)
           response.status(500).send(error)
       })
        })