基于括号出现次数重复打印指定字符串的技术需求问询

First, let's break down the problem step by step. We need to count every parenthesis in the given string, then print the entire string that many times.

Let's start by manually counting the parentheses in the string to verify:

Einstein found out (apple) (fruit) which is (red)(green) in colour

Each pair of parentheses adds two to the total count:

• (apple) → 2 parentheses
• (fruit) → 2 parentheses
• (red) → 2 parentheses
• (green) → 2 parentheses

Total: 2 + 2 + 2 + 2 = 8 parentheses total.

Now, here's a straightforward Python code snippet to automate this task:

my_strng = "Einstein found out (apple) (fruit) which is (red)(green) in colour"

# Calculate total number of parentheses
parentheses_count = my_strng.count('(') + my_strng.count(')')

# Print the string exactly parentheses_count times
for _ in range(parentheses_count):
    print(my_strng)

How this code works: #

1. Define the input string: We assign the given text to the variable my_strng.
2. Count parentheses: Using Python's built-in count() method, we tally up all opening ( and closing ) brackets separately and add them together.
3. Repeat the string: We use a loop to print the full string once for every parenthesis counted.

Expected Output: #

When you run this code, it will print the original string 8 times in sequence:

Einstein found out (apple) (fruit) which is (red)(green) in colour
Einstein found out (apple) (fruit) which is (red)(green) in colour
Einstein found out (apple) (fruit) which is (red)(green) in colour
Einstein found out (apple) (fruit) which is (red)(green) in colour
Einstein found out (apple) (fruit) which is (red)(green) in colour
Einstein found out (apple) (fruit) which is (red)(green) in colour
Einstein found out (apple) (fruit) which is (red)(green) in colour
Einstein found out (apple) (fruit) which is (red)(green) in colour

内容的提问来源于stack exchange，提问作者Prabu