运行基于BeautifulSoup的RSS解析代码出现AttributeError，求解决

Hey there! Let's break down why you're getting that AttributeError: 'NavigableString' object has no attribute 'text' error and fix your code step by step.

错误根源 #

Your code has a small issue with how you're accessing the <link> tags. When you do xml.findAll('link')[3], you're grabbing the 4th <link> tag (since Python uses 0-indexing) from the RSS feed. Then you try to loop over this single tag with for item in xml.findAll('link')[3] — but looping over a BeautifulSoup tag actually iterates over its child nodes, which are NavigableString objects (plain text), not tags. These string objects don't have a .text attribute, hence the error.

Plus, in standard RSS feeds, the news links you want are nested inside <item> tags, not just top-level <link> tags. Your original approach was targeting the wrong elements entirely.

修复后的代码（遍历所有新闻条目） #

Here's a corrected version that properly fetches each news link from the RSS feed and reads the content:

from bs4 import BeautifulSoup
import urllib.request

# Fetch and parse the RSS feed
rss_url = "https://www.theguardian.com/international/rss"
response = urllib.request.urlopen(rss_url)
xml_soup = BeautifulSoup(response, features='xml')

# Get all news items (each <item> tag represents one news story)
news_items = xml_soup.findAll('item')

for item in news_items:
    # Extract the link from the current news item
    news_link = item.find('link').text
    print(f"News Link: {news_link}")
    
    # Fetch the news page content and decode it to a readable string
    news_page_response = urllib.request.urlopen(news_link)
    news_content = news_page_response.read().decode('utf-8')
    
    # Print a preview of the content (adjust the slice length as needed)
    print(f"Content Preview: {news_content[:500]}...\n")

关键改进点 #

• We first grab all <item> tags (these are the individual news entries in the RSS feed)
• For each item, we use item.find('link') to get the specific link tag inside that news entry
• We decode the raw response from read() using .decode('utf-8') to convert it from binary data to a human-readable string

如果只想获取单个特定链接 #

If you actually wanted to target just the 4th <link> tag (like your original code tried), here's how to do it without looping:

from bs4 import BeautifulSoup
import urllib.request

rss_url = "https://www.theguardian.com/international/rss"
response = urllib.request.urlopen(rss_url)
xml_soup = BeautifulSoup(response, features='xml')

# Get the 4th <link> tag (index 3)
target_link = xml_soup.findAll('link')[3]
# Access its text directly (no need to loop)
print(f"Target Link: {target_link.text}")

# Fetch and read the page content
news_page_response = urllib.request.urlopen(target_link.text)
news_content = news_page_response.read().decode('utf-8')
print(news_content[:500])

内容的提问来源于stack exchange，提问作者Asma singh