在Kotlin中如何调用JTable.getColumn？调用抛参数异常求解决

Hey there! I’ve run into this exact pitfall before—let’s break down what’s happening and how to fix it quickly.

Why the error happens #

The JTable.getColumn() method does not take a column index as its argument. Instead, it expects a column identifier (an object that uniquely identifies the column, which defaults to the column name if you didn’t set a custom one). When you pass 0 (an integer), the JTable tries to find a column with 0 as its identifier—and since that doesn’t exist, it throws the IllegalArgumentException: Identifier not found error.

Correct ways to get a column in Kotlin #

Here are two reliable approaches depending on what you need:

1. Get column by index (what you probably intended) #

To fetch a column using its position index, use the table’s ColumnModel instead:

val yourTable = JTable(...)
// Get the first column (index 0)
val targetColumn = yourTable.columnModel.getColumn(0)

Kotlin lets you use property access syntax for columnModel, so this works too:

val targetColumn = yourTable.columnModel[0]

2. Get column by identifier (if you need this specifically) #

If you really want to use JTable.getColumn(), make sure you pass the correct identifier for the column. For example:

• If you’re using default column names:

  // Assuming your first column is named "User ID"
  val targetColumn = yourTable.getColumn("User ID")
  

• If you set a custom identifier when creating the column:

  // Create a column with a custom identifier
  val customColumn = TableColumn(0).apply {
      identifier = "user_identifier"
  }
  yourTable.columnModel.addColumn(customColumn)
  
  // Fetch using the custom identifier
  val targetColumn = yourTable.getColumn("user_identifier")
  

Quick recap #

• Use table.columnModel.getColumn(index) when you know the column’s position.
• Use table.getColumn(identifier) only when you have the column’s unique identifier (not its index).

内容的提问来源于stack exchange，提问作者paj28