如何递归执行grep并排除一级子目录下的指定二级子目录？

Great question—dealing with tons of first-level subdirectories makes manual exclusion totally impractical, so let’s fix this with a smarter grep pattern. Here’s exactly how to skip all /idc and /otherStuffIdc sub-subdirectories, no matter which first-level folder they live under:

The Command You Need #

Use wildcard patterns in the --exclude-dir option to target any parent directory followed by your unwanted sub-subdirectories:

grep -r "searchTerm" --exclude-dir='*/idc' --exclude-dir='*/otherStuffIdc' .

If you prefer combining the exclusions into a single flag (just make sure there are no spaces inside the curly braces):

grep -r "searchTerm" --exclude-dir={*/idc,*/otherStuffIdc} .

How This Works #

• The */ wildcard matches any first-level subdirectory (like subdir1, subdir2, etc.) in your root search folder.
• Adding idc or otherStuffIdc after the wildcard tells grep to skip any directory that ends with /idc or /otherStuffIdc—which perfectly targets those sub-subdirectories under every first-level folder you have.

Quick Example to Verify #

If your directory structure looks like this:

/folder/
├─ subdir1/
│  ├─ idc/
│  ├─ files/
│  └─ otherStuffIdc/
├─ subdir2/
│  ├─ idc/
│  └─ files/
└─ ... (many more first-level subdirs)

The command will skip subdir1/idc, subdir1/otherStuffIdc, subdir2/idc, and all identical sub-subdirectories under every other first-level folder—while still searching through the files/ directories and any other valid folders you care about.

内容的提问来源于stack exchange，提问作者Steve