Android深度链接配置问题：点击可变参数URL无法唤起应用

Alright, let's break down why your current configuration isn't working and how to fix it. The key problem here is how Android handles the # (fragment) in your URL.

Why Your Current Setup Fails #

Your target URL is https://myportal.net/#!/search/main/34. Notice the # symbol? Everything after it is considered a URI fragment—Android's <intent-filter> doesn't use fragments to match <data> attributes like pathPattern. Your existing pathPattern="/.*/.*/.*/.*" is trying to match parts of the URL's path, but in this case, the actual path (before the #) is empty. So the system never triggers your SplashActivity.

Solution 1: Adjust the Intent Filter & Parse the Fragment #

Since you can't change the URL structure (with the #!), we'll modify the intent filter to match just the scheme and host, then manually parse the fragment in code to extract the variable number.

Step 1: Update the Intent Filter

Change your <intent-filter> to only match the https scheme and your host. Remove the pathPattern since it won't work with fragments:

<activity android:name="ui.Activities.SplashActivity" 
          android:configChanges="orientation|keyboardHidden|screenSize" 
          android:theme="@style/SplashScreen">
    <intent-filter android:label="@string/app_name">
        <action android:name="android.intent.action.VIEW" />
        <category android:name="android.intent.category.DEFAULT" />
        <category android:name="android.intent.category.BROWSABLE" />
        <!-- Match only scheme and host; fragment will be handled in code -->
        <data android:host="${hostName}" 
              android:scheme="https" />
    </intent-filter>
</activity>

Make sure ${hostName} is correctly resolved to myportal.net in your build config, or replace it directly with the host string for testing.

Step 2: Parse the Fragment in Your Activity

In SplashActivity, retrieve the fragment from the intent's URI and extract the variable number:

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    
    // Handle deep link intent
    Intent incomingIntent = getIntent();
    Uri deepLinkUri = incomingIntent.getData();
    
    if (deepLinkUri != null) {
        String fragment = deepLinkUri.getFragment();
        // The fragment will be "!/search/main/34" from your URL
        if (fragment != null && fragment.startsWith("!/")) {
            // Strip the leading "!/" to get the path segments
            String pathSegments = fragment.substring(2);
            String[] parts = pathSegments.split("/");
            
            // Check if we have the expected segments
            if (parts.length >= 3) {
                String variableId = parts[2]; // This will be "34" (or any other number)
                // Now navigate to your target screen with this ID
                Intent targetIntent = new Intent(this, YourTargetActivity.class);
                targetIntent.putExtra("ITEM_ID", variableId);
                startActivity(targetIntent);
                finish(); // Optional: close SplashActivity after navigation
            }
        }
    }
    
    // Rest of your SplashActivity initialization code
}

Step 3: Test the Deep Link #

Use this adb command to test if the link opens your app correctly:

adb shell am start -W -a android.intent.action.VIEW -d "https://myportal.net/#!/search/main/34" com.your.app.package

Replace com.your.app.package with your app's actual package name.

Bonus: If You Can Modify the URL #

If you have control over the URL structure, remove the #! to make it a standard path: https://myportal.net/search/main/34. Then you can use a pathPattern like "/search/main/.*" to directly match the variable:

<data android:host="${hostName}" 
      android:pathPattern="/search/main/.*" 
      android:scheme="https" />

This way, you can extract the ID directly from deepLinkUri.getLastPathSegment() without parsing the fragment.

内容的提问来源于stack exchange，提问作者Ahmad Nasser