Python循环中如何累加计算多套餐订单的总消费金额？

需新增/修改的代码说明 #

1. 先修复原有代码的逻辑错误：原判断语句combo != 'x' and 'X'、combo == 'a' and 'A'写法不符合Python逻辑，无法正确识别大小写输入，甚至会导致输入X后无法正常退出循环，统一用.lower()方法转小写后判断即可解决。
2. 新增总价累加逻辑：
   • 循环执行前初始化一个总金额变量，初始值设为0
   • 每次计算完单种套餐的订单价格后，把该价格加到总金额变量中
   • 循环结束后输出总金额即可

修改后的完整代码 #

# 新增：初始化总金额变量
total_price = 0
combo = str(input('Enter Combo Type (A/B/C or X to end) ='))

# 修正while判断逻辑，转小写后判断
while combo.lower() != 'x':
    if combo.lower() == 'a':
        qtt = int(input('How many do you want to order  ='))
        price = qtt * 40
        # 新增：累加当前套餐价格到总金额
        total_price += price
        print('Order price for combo A =', price)
        combo = str(input('Enter Combo Type (A/B/C or X to end) ='))
    elif combo.lower() == 'b':
        qtt = int(input('How many do you want to order  ='))
        price = qtt * 52
        total_price += price
        print('Order price for combo B =', price)
        combo = str(input('Enter Combo Type (A/B/C or X to end) ='))
    elif combo.lower() == 'c':
        qtt = int(input('How many do you want to order  ='))
        price = qtt * 46
        total_price += price
        print('Order price for combo C =', price)
        combo = str(input('Enter Combo Type (A/B/C or X to end) ='))
    else:
        print("Wrong input, please try again.")
        combo = str(input('Enter Combo Type (A/B/C or X to end) ='))

# 新增：循环结束后输出总金额
print('Total order price for all combos =', total_price)

内容的提问来源于stack exchange，提问作者Jane Lam