Python3中isdigit语法错误问题及猜数字代码功能优化求助

Hey there! Let's work through your code issues one by one and add that "ur close" feature you want.

First: Fix the Syntax Error #

The line if n not n.isdigit(): throws a syntax error because of incorrect logic structure. The right way to check if the input isn't a valid digit is if not n.isdigit() — the not keyword needs to come directly before the method call to negate its boolean result.

Second: Fix Hidden Type Mismatch Error #

Your input n is a string (from the input() function), but you're trying to compare it directly to the integer x (generated by random.randint()). This will trigger a TypeError since you can't compare strings and integers directly. After confirming the input is a digit, convert it to an integer with n = int(n).

Third: Add the "Ur Close" Feature #

To check if the guess is within ±20 of the target number, calculate the absolute difference between the guessed number and x using abs(n - x). If that difference is ≤20, print your "ur close" message. Make sure to do this after converting n to an integer but before checking if it's higher or lower than x.

Bonus: Adjust Input Check Order #

Right now, if you enter "Q", the code first tries to check if it's in the valid number range (which will fail because "Q" is a string). Let's reorder the checks so we first handle the quit command, then validate if it's a digit, then check the range. That makes the code flow more logical.

Here's the Modified Code #

import random
x = random.randint(0, 100)
i = 0
while True:
    n = input("sheitanet ricxvi an Q gamosvlistvis: ")
    
    # First check if user wants to quit
    if n == "Q":
        print("Bye Bye!")
        break
    
    # Check if input is a valid digit
    if not n.isdigit():
        print("gtxovt sheitanot ricxvi an Q")
        continue
    
    # Convert input to integer now that we know it's a digit
    n = int(n)
    
    # Check if number is within 0-100 range
    if n >= 101 or n < 0:
        print("sheikvanet ricxvi 0 dan 100 is shualedshi!!!!")
        continue
    
    # Add the "ur close" check
    if abs(n - x) <= 20:
        print("ur close")
    
    # Check if guess is correct
    if n == x:
        print("Tqven gamoicanit chafiqrebuli ricxvi!", i, "Cdashi")
        break
    elif n < x:
        print("tqveni shetanili ricxvi naklebia chafiqrebul ricxvze")
        i += 1
    elif n > x:
        print("tqveni ricxvi metia chafiqrebul ricxzze")
        i += 1

Key changes explained:

• Fixed the isdigit() check syntax to use proper negation
• Reordered input checks to handle the quit command first
• Added n = int(n) to convert valid digit inputs to integers for numeric comparisons
• Added the abs(n - x) <= 20 condition to show the "ur close" hint
• Ensured invalid inputs (non-digit, out of range) don't increment the attempt counter i

内容的提问来源于stack exchange，提问作者Sandro Gamrekelashvili