Python中如何用变量动态设置schedule模块的day属性？

云上老周

2026-5-14

解决schedule模块动态指定星期属性的问题

Hey there! No worries about terminology—we’ve all fumbled through new libraries as Python beginners 😊 Let’s break down your problem and fix that error.

问题原因

When you write schedule.every().dayArray[i], Python thinks you’re trying to access an attribute named dayArray directly on the Job object returned by every()—which doesn’t exist, hence the AttributeError. The .sunday/.monday syntax is accessing pre-defined attributes of the Job object, and you can’t use a variable name directly with dot notation like that.

解决方案：使用`getattr()`函数

Python’s built-in getattr() function is exactly what you need here. It lets you dynamically access an object’s attribute using a string name. Here’s how to adjust your code:

import schedule

def job():
    print("Scheduled job executed!")

dayArray = ['sunday', 'monday', 'tuesday', 'wednesday', 'thursday', 'friday', 'saturday']
# 假设xlsxSheet是你已加载的Excel工作表对象
for i in range(0, 7):  # 注意：原range(0,6)会漏掉最后一个周六，这里调整为7覆盖全部星期
    time_value = str(xlsxSheet.cell_value(i+18, 1))
    if time_value != 'NA':
        # 用getattr动态获取对应星期的属性
        getattr(schedule.every(), dayArray[i]).at(time_value).do(job)

为什么这能行？

getattr(schedule.every(), dayArray[i])会把dayArray[i]对应的字符串（比如'sunday'）作为属性名，从Job对象上获取对应的属性——这和直接写schedule.every().sunday的效果完全一致。
我们调整了循环范围到range(0,7)，确保你的星期数组里的所有元素都会被遍历到。