Python获取WiFi SSID报IndentationError缩进错误的解决方法

问题原因 #

你遇到的IndentationError: expected an indented block错误由Python语法的强制缩进规则触发，原始代码存在两处语法问题：

• 对应「WiFi存在安全密钥」逻辑的else:分支下的代码未做缩进，违反Python语法要求
• 密码判空逻辑的else后缺少英文冒号，会额外触发语法错误

修正后完整代码 #

import subprocess
import re

command_output = subprocess.run(["netsh", "wlan", "show", "profiles"], capture_output = True).stdout.decode()
profile_names = re.findall("All User Profile       : (.*)\r", command_output)
wifi_list = list()

if len(profile_names) != 0:
    for name in profile_names:
        wifi_profile = dict()
        profile_info = subprocess.run(["netsh", "wlan", "show", "profile", name], capture_output = True).stdout.decode()
        if re.search("Security key           : Absent", profile_info):
            continue
        else:
            wifi_profile["ssid"] = name
            profile_info_pass = subprocess.run(["netsh", "wlan", "show", "profile", name, "key=clear"], capture_output = True).stdout.decode()
            password = re.search("Key Content            : (.*)\r", profile_info_pass)
            if password == None:
                wifi_profile["password"] = None
            else:
                wifi_profile["password"] = password[1]
            wifi_list.append(wifi_profile)

for x in range(len(wifi_list)):
    print(wifi_list[x])

内容的提问来源于stack exchange，提问作者Hassan Ali