PHP中按id_gudang和id_receiver分组求和多维数组price值

嘿，这个需求我经常碰到，给你两种实用的实现方式，都能完美达到你的要求：

方法一：遍历数组+临时存储（最直观易读） #

这种方式逻辑清晰，新手也能轻松理解，核心是用唯一组合键来区分不同的id_gudang+id_receiver配对：

<?php
$data = [
    ['id_gudang' => 69, 'id_receiver' => 121, 'price' => 1],
    ['id_gudang' => 69, 'id_receiver' => 121, 'price' => 3],
    ['id_gudang' => 71, 'id_receiver' => 134, 'price' => 7],
    ['id_gudang' => 72, 'id_receiver' => 135, 'price' => 3],
    ['id_gudang' => 72, 'id_receiver' => 216, 'price' => 5],
    ['id_gudang' => 72, 'id_receiver' => 216, 'price' => 5]
];

// 用临时数组存储累加后的结果
$temp = [];
foreach ($data as $item) {
    // 拼接唯一键：用不会出现在ID里的字符分隔，避免冲突
    $key = $item['id_gudang'] . '|' . $item['id_receiver'];
    
    if (isset($temp[$key])) {
        // 已存在该组合，累加price
        $temp[$key]['price'] += $item['price'];
    } else {
        // 首次出现该组合，直接存入临时数组
        $temp[$key] = $item;
    }
}

// 把关联数组转成索引数组，得到最终结果
$new_data = array_values($temp);

print_r($new_data);
?>

逻辑说明： #

1. 遍历原始数组时，用id_gudang和id_receiver拼接成唯一的键（这里用|做分隔符，比下划线更安全，避免ID本身含下划线导致键冲突）；
2. 检查临时数组中是否存在这个键：存在就累加价格，不存在就把当前项存入；
3. 最后用array_values()把临时数组的关联键去掉，转换成你需要的索引数组格式。

方法二：用array_reduce函数（更简洁的函数式写法） #

如果你喜欢更简洁的代码，可以用PHP的array_reduce函数来实现，本质逻辑和方法一完全一致，只是写法更紧凑：

<?php
$data = [
    ['id_gudang' => 69, 'id_receiver' => 121, 'price' => 1],
    ['id_gudang' => 69, 'id_receiver' => 121, 'price' => 3],
    ['id_gudang' => 71, 'id_receiver' => 134, 'price' => 7],
    ['id_gudang' => 72, 'id_receiver' => 135, 'price' => 3],
    ['id_gudang' => 72, 'id_receiver' => 216, 'price' => 5],
    ['id_gudang' => 72, 'id_receiver' => 216, 'price' => 5]
];

$new_data = array_values(array_reduce($data, function ($carry, $item) {
    $key = $item['id_gudang'] . '|' . $item['id_receiver'];
    if (isset($carry[$key])) {
        $carry[$key]['price'] += $item['price'];
    } else {
        $carry[$key] = $item;
    }
    return $carry;
}, []));

print_r($new_data);
?>

逻辑说明： #

array_reduce会迭代原始数组，把每一项逐步合并到$carry（累加器）中，我们在回调函数里完成和方法一相同的键判断与价格累加，最后同样用array_values()转换数组格式。

两种方法运行后，都会得到你期望的$new_data数组哦～

内容的提问来源于stack exchange，提问作者rifqi shiddiq