如何在Frida中正确重载带有int参数的函数？

Let's break down what went wrong and fix your Frida script step by step.

First, looking at your code and error message:

• You tried to hook a method named cleanUi instead of your target method getState
• The error message clearly lists all available overloads for getState, including the one you need: .overload('java.lang.String', 'int')

Here's the corrected Frida script to intercept your getState method properly:

// 获取目标Activity类
var AppActivity = Java.use('com.myapp.AppActivity');

// 指定getState的正确重载：第一个参数是String，第二个是int基本类型
AppActivity.getState.overload('java.lang.String', 'int').implementation = function(str, i) {
    // 打印拦截到的参数信息
    console.log(`🔍 Intercepted getState call:`);
    console.log(`   Key: ${str}`);
    console.log(`   Default value: ${i}`);

    // 调用原方法获取原始返回值（必须调用，否则会破坏原程序逻辑）
    var originalReturnValue = this.getState(str, i);
    
    // 可以在这里修改返回值，或者直接返回原结果
    console.log(`   Original return value: ${originalReturnValue}`);
    return originalReturnValue;
};

Key Notes to Remember: #

1. Target the Right Method: Make sure you're hooking getState (your target method) instead of unrelated methods like cleanUi as you did earlier.
2. Match Parameter Types Exactly:
   • For Java reference types (like String), use their full class name: java.lang.String
   • For primitive types (like int, float, boolean), use the simple type name directly (not their wrapper classes like java.lang.Integer)
3. Call the Original Method: Always invoke the original method with this.getState(str, i) and return its result (or your modified value) — skipping this will cause unexpected behavior in the app.

Bonus: How to Verify Method Signatures #

If you're ever unsure about a method's overloads, you can use this Frida snippet to list all available signatures for your target class:

Java.enumerateMethods('com.myapp.AppActivity.getState*', {
    onMatch: function(method) {
        console.log(`Found method: ${method.signature}`);
    },
    onComplete: function() {
        console.log('Done enumerating methods');
    }
});

内容的提问来源于stack exchange，提问作者E235