如何无需指定列表名，对字典内嵌套列表的数值求和？

Got it, let's fix this without having to hardcode each key name—this is straightforward with a Python dictionary comprehension, which lets us process every key-value pair dynamically.

Complete Working Code #

Here's the code that does exactly what you need, no manual key specification required:

original_dict = {'swimming': ['1000', '1200'], 'fencing': ['200', '100'], 'athletics': ['600']}

result_dict = {
    key: [str(sum(int(num_str) for num_str in value_list))]
    for key, value_list in original_dict.items()
}

print(result_dict)

How This Works (Breakdown) #

Let's walk through each part so you understand the magic:

• original_dict.items() loops through every key and its corresponding list in the dictionary—no need to name each sport explicitly!
• For each list of string numbers, we use int(num_str) to convert each string to an integer, then pass those integers to sum() to get the total.
• We convert the sum back to a string (to match your desired output format) and wrap it in a list [str(...)] to keep the nested structure you want.
• The dictionary comprehension builds the new dictionary with the original keys and the processed summed values.

Expected Output #

Running this code will give you the exact structure you're targeting:

{'swimming': ['2200'], 'fencing': ['300'], 'athletics': ['600']}

This approach is also scalable—if you add more sports to your original dictionary later, the code will handle them automatically without any changes.

内容的提问来源于stack exchange，提问作者Fletcher Adams