Zapier搜索功能报错：期望返回数组却得到对象的技术咨询

Hey there, the error you're hitting is a simple format mismatch: Zapier requires search operations to return an array of results, but your custom API sends back a single JSON object. Even if you only ever expect one matching item, Zapier needs that result wrapped in an array to process it correctly.

The Quick Fix #

Modify your perform function to wrap the parsed API response in an array. Here's the adjusted code:

module.exports = {
  key: 'item',
  noun: 'itemexists',
  display: {
    label: 'Find an item',
    description: 'check if item exist'
  },
  operation: {
    inputFields: [
      {
        key: 'itemid',
        type: 'string',
        label: 'itemid',
        helpText: 'Eg. e3f1a92f72c901ffc942'
      }
    ],
    perform: (z, bundle) => {
      const url = 'http://IP:8081/v1/itemexists/';
      const options = {
        params: {
          itemId: bundle.inputData.itemid
        }
      };
      // Wrap the parsed response object in an array
      return z.request(url, options)
        .then(response => [JSON.parse(response.content)]);
    },
    sample: {"exists": true, "data": {"creationDate": "2019-05-23T10:11:18.514Z", "Type": "Test", "status": 1, "Id": "456gf934a8aefdcab2eadfd22861", "value": "Test"}},
  }
};

Optional Adjustment (If You Only Need the data Field) #

If you don't need to pass the exists flag to Zapier and just want the item details, you can tweak the return line to pull out the data property instead:

return [JSON.parse(response.content).data];

Just make sure your sample object is updated to match this structure if you go this route—Zapier uses the sample to generate previews and map fields.

内容的提问来源于stack exchange，提问作者TechChain