PHP如何将营业时间数组转换为自然语言描述字符串

你已经完成了按营业时间分组的核心逻辑，后续只需要4步即可生成符合阅读习惯的字符串：

• 第一步：提前定义星期映射表，包含「星期全名转缩写」「星期排序权重」两个映射，用来处理日期的格式化和连续段判断
• 第二步：对每个营业时间分组下的日期列表，先按星期顺序排序，再把连续的日期合并成「X to Y」的格式，不连续的单独保留
• 第三步：把同一分组下合并后的日期段用and拼接成完整的日期前缀
• 第四步：把所有分组的「日期前缀: 时间段」用逗号拼接，得到最终结果

<?php
// 定义星期映射：[全名 => [缩写, 排序权重]]
$weekMap = [
    'monday' => ['mon', 1],
    'tuesday' => ['tue', 2],
    'wednesday' => ['wed', 3],
    'thursday' => ['thu', 4],
    'friday' => ['fri', 5],
    'saturday' => ['sat', 6],
    'sunday' => ['sun', 7]
];

$openHoursJson = '{"monday":{"working":"yes","open":"09:00","close":"17:00"},"tuesday":{"working":"yes","open":"09:00","close":"17:00"},"wednesday":{"working":"yes","open":"09:00","close":"17:00"},"thursday":{"working":"yes","open":"09:00","close":"18:00"},"friday":{"working":"yes","open":"09:00","close":"17:00"},"saturday":{"working":"yes","open":"09:00","close":"14:00"},"sunday":{"open":"00:00","close":"00:00"}}';
$openHoursArray = json_decode($openHoursJson, true);

$openHoursReduced = [];
foreach ($openHoursArray as $dayOfWeek => $dayConfigs) {
    if(!empty($dayConfigs['working']) && $dayConfigs['working'] == 'yes'){
        $hoursStr = sprintf('%s to %s', $dayConfigs['open'], $dayConfigs['close']);
        $openHoursReduced[$hoursStr][] = $dayOfWeek;
    }
}

// 处理每个分组的日期拼接
$finalParts = [];
foreach ($openHoursReduced as $hours => $dayList) {
    // 1. 给日期按周顺序排序
    usort($dayList, function($a, $b) use ($weekMap) {
        return $weekMap[$a][1] - $weekMap[$b][1];
    });

    // 2. 合并连续日期段
    $merged = [];
    $currentSegment = [$dayList[0]];
    for ($i = 1; $i < count($dayList); $i++) {
        $prevWeight = $weekMap[$dayList[$i-1]][1];
        $currentWeight = $weekMap[$dayList[$i]][1];
        if ($currentWeight == $prevWeight + 1) {
            $currentSegment[] = $dayList[$i];
        } else {
            $merged[] = $currentSegment;
            $currentSegment = [$dayList[$i]];
        }
    }
    $merged[] = $currentSegment;

    // 3. 把合并后的段转成字符串
    $segmentStrs = [];
    foreach ($merged as $seg) {
        if (count($seg) == 1) {
            $segmentStrs[] = $weekMap[$seg[0]][0];
        } else {
            $segmentStrs[] = $weekMap[$seg[0]][0] . ' to ' . $weekMap[end($seg)][0];
        }
    }
    $dayStr = implode(' and ', $segmentStrs);

    // 4. 拼装当前分组的完整描述
    $finalParts[] = $dayStr . ': ' . $hours;
}

// 最终拼接所有分组
$result = implode(', ', $finalParts);
echo $result;
?>

输出完全符合你给出的预期：
mon to wed and fri: 09:00 to 17:00, thu: 09:00 to 18:00, sat: 09:00 to 14:00

如果不需要and，把implode(' and ', $segmentStrs)改成implode(', ', $segmentStrs)即可。

内容的提问来源于stack exchange，提问作者endeavour