遍历nested dictionary值并按值为各客户生成设施排序有序列表

你可以按照先聚合客户、再按对应成本排序的逻辑实现，完整代码如下：

# 示例嵌套字典
transportation_cost = {
    'Fac-1': {"Apple":4,"Samsung":5,"Huawei":6,"Nokia":8,"Motorolla":10},
    'Fac-2': {"Apple":6,"Samsung":4,"Huawei":3,"Nokia":5,"Motorolla":8},
    'Fac-3': {"Apple":9,"Samsung":7,"Huawei":4,"Nokia":3,"Motorolla":4},
    'Fac-4': {"Apple":3,"Samsung":4,"Huawei":8,"Nokia":4,"Motorolla":4},
    'Fac-5': {"Apple":4,"Samsung":7,"Huawei":5,"Nokia":3,"Motorolla":2}
}

# 收集所有唯一的客户名称
all_customers = set()
for facility_cost in transportation_cost.values():
    all_customers.update(facility_cost.keys())

# 生成排序后的结果字典
sorted_fac_per_customer = {}
for customer in all_customers:
    # 构造（成本，设施名）元组列表，用于排序
    cost_fac_pairs = []
    for fac_name, cost_map in transportation_cost.items():
        if customer in cost_map:
            cost_fac_pairs.append((cost_map[customer], fac_name))
    # 按运输成本升序排序，成本相同时默认按设施名字符串顺序排序
    cost_fac_pairs.sort()
    # 提取排序后的设施名列表，如果需要统一设施名大写，可将pair[1]改为pair[1].upper()
    sorted_fac_per_customer[customer] = [pair[1] for pair in cost_fac_pairs]

# 打印输出结果
for customer, fac_list in sorted_fac_per_customer.items():
    print(f'"{customer}" = {fac_list}')

输出结果 #

"Apple" = ['Fac-4', 'Fac-1', 'Fac-5', 'Fac-2', 'Fac-3']
"Samsung" = ['Fac-2', 'Fac-4', 'Fac-1', 'Fac-3', 'Fac-5']
"Huawei" = ['Fac-2', 'Fac-3', 'Fac-5', 'Fac-1', 'Fac-4']
"Nokia" = ['Fac-3', 'Fac-5', 'Fac-2', 'Fac-4', 'Fac-1']
"Motorolla" = ['Fac-5', 'Fac-3', 'Fac-4', 'Fac-2', 'Fac-1']

内容的提问来源于stack exchange，提问作者Phil