如何基于布尔数组的取值打印另一数组对应位置的数值

修正后可运行的实现代码 #

原代码存在字典未闭合、键名不匹配、未逐位遍历数组匹配值的问题，修正后实现逻辑如下：

times = {
  "times1": ["8","9","10","11","12","13","14","15","16","17"],
  "times2": ["8","9","10","11","12","13","14","15","16","17"],
  "times3": ["8","9","10","11","12","13","14","15","16","17"],
  "times4": ["8","9","10","11","12","13","14","15","16","17"],
  "times5": ["8","9","10","11","12","13","14","15","16","17"],
  "times6": ["8","9","10","11","12","13","14","15","16","17"],
  "times7": ["8","9","10","11","12","13","14","15","16","17"],
  "times8": ["8","9","10","11","12","13","14","15","16","17"]
}
access = {
  "access1": [True,False,False,True,True,False,False,False,True,True],
  "access2": [False,False,True,True,False,False,False,False,True,True],
  "access3": [False,False,False,True,True,False,True,False,True,False],
  "access4": [True,True,False,True,True,True,False,False,True,True],
  "access5": [True,False,False,True,True,False,False,False,True,False],
  "access6": [True,False,False,True,True,False,True,True,False,True],
  "access7": [True,True,True,True,True,False,False,False,True,True],
  "access8": [True,False,True,True,False,False,False,False,True,True]
}

# 按编号匹配对应球场的时间数组和状态数组
for idx in range(1,9):
    time_arr = times[f"times{idx}"]
    access_arr = access[f"access{idx}"]
    print(f"球场{idx}不可用时段：")
    # 逐位配对时间和状态，状态为False时打印对应时间
    for time_val, access_val in zip(time_arr, access_arr):
        if not access_val:
            print(f"{time_val}点")
    print("---")

如果仅需要输出时间值不需要额外说明，可以简化循环逻辑：

for idx in range(1,9):
    for t, a in zip(times[f"times{idx}"], access[f"access{idx}"]):
        if not a:
            print(t)

内容的提问来源于stack exchange，提问作者Raphael Nogueira Costa