如何实现点击按钮切换Tkinter窗口的OptionMenu下拉菜单内容

你原有代码存在两个核心问题：

• 链式调用pack()导致optionmenu1和optionmenu2实际存储的是None（pack()方法无返回值），无法后续操作控件实例
• 两个下拉菜单同时被渲染到界面上，没有做隐藏处理

方案1（推荐）：动态修改单个OptionMenu的选项 #

无需创建两个独立下拉控件，直接修改同一个控件的菜单列表即可，性能更高逻辑更简洁：

from tkinter import Tk, StringVar, OptionMenu, Button

root = Tk()
root.geometry("300x200")

var = StringVar()
var.set("Select your iPhone")
options1 = ["         b1        ", "   b2     "," b3", "    b4    ","         b5        ","    b6    ","         b7       "]
option2 = ["b8"]

# 单独调用pack，保留控件实例
om = OptionMenu(root, var, *options1)
om.pack(pady=20)

def switch_options():
    # 清空原有选项
    menu = om['menu']
    menu.delete(0, 'end')
    # 添加新选项
    for opt in option2:
        menu.add_command(label=opt, command=lambda value=opt: var.set(value))
    # 重置选中提示
    var.set("Select your iPhone")

# 绑定切换按钮
btn = Button(root, text="切换选项", command=switch_options)
btn.pack(pady=10)

root.mainloop()

方案2：切换两个预先创建的OptionMenu #

如果你确实需要保留两个独立的下拉控件，可通过显示/隐藏实现切换：

from tkinter import Tk, StringVar, OptionMenu, Button

root = Tk()
root.geometry("300x200")

var = StringVar()
var.set("Select your iPhone")
options1 = ["         b1        ", "   b2     "," b3", "    b4    ","         b5        ","    b6    ","         b7       "]
option2 = ["b8"]

# 只默认显示第一个下拉菜单
om1 = OptionMenu(root, var, *options1)
om1.pack(pady=20)
om2 = OptionMenu(root, var, *option2)

show_om1 = True
def switch_om():
    global show_om1
    if show_om1:
        om1.pack_forget()
        om2.pack(pady=20)
    else:
        om2.pack_forget()
        om1.pack(pady=20)
    show_om1 = not show_om1
    var.set("Select your iPhone")

btn = Button(root, text="切换下拉菜单", command=switch_om)
btn.pack(pady=10)

root.mainloop()

内容的提问来源于stack exchange，提问作者Nomore