如何将列表中相邻差值不为1的元素拆分到多个独立子列表中

拆分结果 #

• list1 = [29]
• list2 = [64, 65, 66]
• list3 = [128, 129, 130]
• list4 = [166, 167, 168]
• list5 = [184, 185, 186]
• list6 = [215, 216, 217]
• list7 = [237, 238, 239]
• list8 = [349, 350, 351]
• list9 = [443]
• list10 = [483, 484, 485]
• list11 = [495, 496, 497]
• list12 = [526, 527, 528]
• list13 = [542, 543, 544]
• list14 = [564, 565, 566]

Python实现代码 #

def split_continuous_lists(nums):
    if not nums:
        return []
    # 初始化结果列表，存入第一个元素作为首个子列表的起始
    result = [[nums[0]]]
    for num in nums[1:]:
        # 当前元素和上一个子列表的末尾元素差值为1则追加，否则新建子列表
        if num - result[-1][-1] == 1:
            result[-1].append(num)
        else:
            result.append([num])
    return result

# 输入待拆分的数字列表
input_nums = [29, 64, 65, 66, 128, 129, 130, 166, 167, 168, 184, 185, 186, 215, 216, 217, 237, 238, 239, 349, 350, 351, 443, 483, 484, 485, 495, 496, 497, 526, 527, 528, 542, 543, 544, 564, 565, 566]
output = split_continuous_lists(input_nums)

# 格式化打印结果
for index, sub_list in enumerate(output, 1):
    print(f"list{index}={sub_list}")

内容的提问来源于stack exchange，提问作者It Engineer