Python文本冒险游戏动作命令触发unhashable type报错如何解决

报错根因 #

你触发TypeError: unhashable type: 'dict'的核心原因是：rooms字典的键均为字符串类型的房间名，而你代码里的current_room本身已经是存储单个房间信息的字典对象，无法作为键传入rooms字典做查询，字典属于不可哈希类型，不能作为字典的键使用。

需要修改的代码点 #

1. 修正初始物品配置 #

将原代码中初始化物品的行：

current_items = None

修改为：

current_items = []

避免后续往物品列表添加元素时出现类型错误。

2. 修正移动命令逻辑 #

原移动命令逻辑存在查询逻辑错误，将原代码：

elif player_action[0] == 'go':
    if player_action[1] in rooms[current_room]:
        current_room = rooms[current_room][player_action[1]]
    else:
        print("You cannot go that way")

修改为：

elif player_action[0] == 'go':
    # 直接判断输入的方向是否存在于当前房间的配置键中
    if player_action[1] in current_room:
        # 先从当前房间拿到目标房间名，再去rooms字典查询对应房间对象
        current_room = rooms[current_room[player_action[1]]]
    else:
        print("You cannot go that way\n")

3. 修正获取物品命令逻辑 #

原获取物品的判断逻辑完全错误，且直接删除房间item键会导致状态展示报错，将原代码：

elif player_action[0] == 'get':
    if player_action[1] in rooms[current_room]:
        current_items += [player_action[1]]
        print("You got: ", player_action[1])
        del rooms[current_room]['item']
    else:
        print("What exactly were you looking for?")

修改为：

elif player_action[0] == 'get':
    # 判断输入的物品名和当前房间存储的物品是否一致，且房间内有可拾取物品
    if player_action[1] == current_room['item'] and current_room['item'] != 'nothing':
        current_items.append(player_action[1])
        print(f"You got: {player_action[1]}\n")
        # 修改物品标记为无，不要删除键避免状态展示报错
        current_room['item'] = 'nothing'
    else:
        print("What exactly were you looking for?\n")

内容的提问来源于stack exchange，提问作者Joseph Wychico