Python十六进制转十进制代码输出科学计数法结果异常如何修复？

1. 核心转换逻辑错误：hexToDec函数中多余执行了i/float(2**21)操作，你需求是直接将十六进制转十进制整数，该除法逻辑完全不符合需求。同时超大整数转float会出现精度丢失，且自动用科学计数法格式化输出，就是你看到3.612432554629948e+76这类结果的原因。
2. 语法错误：代码最后一行的等待输入逻辑写法错误，运行到此处会抛出 TypeError 异常。
3. 异常处理漏洞：如果hex.txt不存在，捕获IOError后没有终止程序，后续遍历未定义的inFile变量会直接报错。

• 删除hexToDec中多余的除法逻辑，直接返回十六进制转成的整数字符串即可
• 修正最后一行的输入提示代码
• 补全文件打开失败后的退出逻辑，改用with上下文管理器优化文件操作，避免资源泄漏

# Covert a file with lines of hex values in "hex.txt" to decimal
# values and write to "dec.txt"

# NOTE: This program only handles Value errors and replaces them
# with the string XXXXX, no other error handling is performed  

HEXLIST_FILENAME = "hex.txt"
DECLIST_FILENAME = "dec.txt"

def loadHex():
    """
    Returns a list of Hex strings from a file
    """
    hexList = []
    print ("Loading hex list from file...")
    try:
        with open(HEXLIST_FILENAME, 'r') as inFile:
            for line in inFile:
                hexList.append(line.strip().upper())
    except IOError:
        print('No such file "hex.txt"')
        exit(1)
    print(len(hexList), "Numbers loaded.")
    return hexList

def hexToDec(hexString):
    """
    Takes in a string representing a hex value
    Returns a decimal number string
    """
    try:
        i = int(hexString,16)
    except ValueError:
        print('Oops! There was an invalid number in hex.txt...')
        print('Invalid number replaced with XXXXX')
        return 'XXXXX'
    return str(i)

def exportDec(decList):
    """
    Writes decimal list to output file
    """
    with open(DECLIST_FILENAME, 'w') as outFile:
        for num in decList:
            outFile.write(num+"\n")
    print ("Success! Decimal numbers written to dec.txt")


decList = []
hexVals = loadHex()
for hexnum in hexVals:
    decList.append(hexToDec(hexnum))

exportDec(decList)

input('Press Enter to exit...')

内容的提问来源于stack exchange，提问作者kamburishka