使用for循环实现URL编码空格转%20的问题排查求助

原有代码问题 #

• 仅在字符为空格时才将内容拼接至结果字符串，非空格字符完全未加入结果，导致输出仅保留替换得到的%20
• 缺少空格计数逻辑，无法实现「第一个空格不替换，后续空格替换为%20」的需求

修复后代码 #

def urlEncode(text):
    result = ''
    space_count = 0
    for char in text:
        if char == ' ':
            space_count += 1
            # 第一个空格直接保留，后续空格替换为%20
            if space_count == 1:
                result += char
            else:
                result += '%20'
        else:
            # 非空格字符直接拼接
            result += char
    return result

# 测试用例
print(urlEncode("Lighthouse Labs"))
print(urlEncode(" Lighthouse Labs  "))
print(urlEncode("blue is greener than purple for sure"))

输出结果 #

Lighthouse Labs
 Lighthouse%20Labs%20%20
blue is%20greener%20than%20purple%20for%20sure

内容的提问来源于stack exchange，提问作者Mohammad